Question

Winnie measured the length of her father's ranch four times and got four different distances. her measurements are shown in the table.
A. To estimate the actual length, winnie first approximated each distance to the nearest hundredth.Then she averaged the four numbers.
Using a calculator, find winnie's estimate.
.
Distance across father's ranch (km)
Square root of 60, 58/8, 7.3, 7 3/5
.
B. Winnie's father estimated the distance across his ranch to be the square root of 56 km. How does this distance compare to Winnie's estimate?

Answer 1

(a) winnie first approximated each distance to the nearest hundredth.

$\sqrt{60} =7.75$

$\frac{58}{8} = 7.25$

7.3 = 7.33

$7\frac{3}{5} = 7.60$

Now we find the average of 4 numbers

$\frac{7.75+7.25+7.33+7.60}{4}$= $\frac{29.93}{4} = 7.4825$

Winnie's estimate = 7.4825

B) Winnie's father estimated the distance across his ranch to be the square root of 56 km

$\sqrt{56} = 7.48331$

Winne's father estimate - Winne's estimate = 7.48331 - 7.48225= 0.00106

Winne's father estimate is 0.00106 more than winne's estimate