I'll just show you how to make a frequency table using the above data.
We will group the data into class intervals and determine the frequency of the group.
<span>8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
</span>
smallest data value = 4
highest data value = 99
difference = 99 - 4 = 95
number of data = 17
Let us assign a class interval of 20.
Class Interval Tally Frequency
0-20 8, 12, 4, 18, 9, 5
21-40 25, 32, 39, 36, 33 5
41-60 45, 50, 67 3
61-80 62, 73, 80 3
81-100 99 1
That is how a frequency table look like. Usually, under the Tally column, tick marks are written instead of the numbers but for easier monitoring, I used the numbers in the data set.
With the choices you gave, the answer to this question is the first statement, "2 loaves of bread and 4 batches of muffins''. I arrived with the answer through multiplying the amount of flour and sugar required for each loaf of bread and batch of muffins.
Answer:
B. 5 and 1/4 percent
Step-by-step explanation:
Step one:
given
principal= $2460
time= 3 and 1/2 years= 3.5 years
SI= $452
Required
The rate
Step two:
we know that
SI= PRT/100
substituting our data we have
452= 2460*R*3.5/100
452=8610R/100
cross multiply
452*100= 8610R
divide both sides by 8610
45200/8610= R
R= 5.25%
R= 5 and 1/4 percent
Answer:
Option B. 
Step-by-step explanation:
we know that
The area of a square is equal to
where
x is the length side of the square
In this problem we have
substitute and solve for x
suqre root both sides
X + x + 1 + x + 2 + x + 3 = 330
4x + 6 = 330
4x = 324, x = 81
Smallest number: 81
Biggest number: 81 + 3 = 84
Sum: 81 + 84 = 165
The answer is 165
