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Alisiya [41]
2 years ago
6

Given a polynomial function f(x), describe the effects on the y-intercept, regions where the graph is increasing and decreasing,

and the end behavior when the following changes are made. Make sure to account for even and odd functions.
When f(x) becomes f(x) − 3
When f(x) becomes −2 ⋅ f(x)

Can someone explain it to me. I dont know how to word it.
Mathematics
2 answers:
masha68 [24]2 years ago
7 0

Answer:

f(x) - 3 is translated 3 units down and -2*f(x) is reflected across x-axis.

Step-by-step explanation:

We have, f(x) becomes f(x) - 3.

The y-intercept of f(x) is f(0), this implies y-intercept of f(x) -3 is f(0) - 3. This means that the graph of f(x) is translated 3 units down.

Next, we have f(x) becomes -2*f(x).

The y-intercept of -2*f(x) is -2*f(0) and it means that first the graph of f(x) is stretched horizontally by 2 units and then reflected across x-axis.

As, the function f(x) is multiplied by 2, this implies that resultant function -2*f(x) will be an even function and its graph will be symmetric about y-axis.

Moreover, the function -2*f(x) increases wherever f(x) decreases and vice-versa.

gogolik [260]2 years ago
5 0

Answer:

f(x) is translated 3 units down and reflected across x-axis.

Step-by-step explanation:

Given : When f(x) becomes f(x) − 3  and  f(x) becomes −2 ⋅ f(x).

To find : describe the effects on the y-intercept, regions where the graph is increasing and decreasing, and the end behavior when the following changes are made. Make sure to account for even and odd functions.

Solution : We have given that :

f(x) becomes f(x) − 3  and  f(x) becomes −2 ⋅ f(x).

By the translation rule :

We have, f(x) becomes f(x) - 3.

The y-intercept of f(x) is f(0), this implies y-intercept of f(x) -3 is f(0) - 3. This means that the graph of f(x) is translated 3 units down.

Next, we have f(x) becomes -2*f(x).

The y-intercept of -2*f(x) is -2*f(0) and it means that first the graph of f(x) is stretched horizontally by 2 units and then reflected across x-axis.

As, the function f(x) is multiplied by 2, this implies that resultant function -2*f(x) will be an even function and its graph will be symmetric about y-axis.

Moreover, the function -2*f(x) increases wherever f(x) decreases and vice-versa

Therefore, f(x) is translated 3 units down and reflected across x-axis.

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A supermarket has two customers waiting to pay for their purchases at counter I and one customer waiting to pay at counter II. L
Pachacha [2.7K]

Answer:

b. 0.864

Step-by-step explanation:

Let's start defining the random variables.

Y1 : ''Number of customers who spend more than $50 on groceries at counter 1''

Y2 : ''Number of customers who spend more than $50 on groceries at counter 2''

If X is a binomial random variable, the probability function for X is :

P(X=x)=(nCx)p^{x}(1-p)^{n-x}

Where P(X=x) is the probability of the random variable X to assume the value x

nCx is the combinatorial number define as :

nCx=\frac{n!}{x!(n-x)!}

n is the number of independent Bernoulli experiments taking place

And p is the success probability.

In counter I :

Y1 ~ Bi (n,p)

Y1 ~ Bi(2,0.2)

P(Y1=y1)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}

With y1 ∈ {0,1,2}

And P( Y1 = y1 ) = 0 with y1 ∉ {0,1,2}

In counter II :

Y2 ~ Bi (n,p)

Y2 ~ Bi (1,0.3)

P(Y2=y2)=(1Cy2)(0.3)^{y2}(0.7)^{1-y2}

With y2 ∈ {0,1}

And P( Y2 = y2 ) = 0 with y2 ∉ {0,1}

(1Cy2) with y2 = 0 and y2 = 1 is equal to 1 so the probability function for Y2 is :

P(Y2=y2)=(0.3)^{y2}(0.7)^{1-y2}

Y1 and Y2 are independent so the joint probability distribution is the product of the Y1 probability function and the Y2 probability function.

P(Y1=y1,Y2=y2)=P(Y1=y1).P(Y2=y2)

P(Y1=y1,Y2=y2)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}(0.3)^{y2}(0.7)^{1-y2}

With y1 ∈ {0,1,2} and y2 ∈ {0,1}

P( Y1 = y1 , Y2 = y2) = 0 when y1 ∉ {0,1,2} or y2 ∉ {0,1}

b. Not more than one of three customers will spend more than $50 can mathematically be expressed as :

Y1 + Y2 \leq 1

Y1 + Y2\leq 1 when Y1 = 0 and Y2 = 0 , when Y1 = 1 and Y2 = 0 and finally when Y1 = 0 and Y2 = 1

To calculate P(Y1+Y2\leq 1) we must sume all the probabilities that satisfy the equation :

P(Y1+Y2\leq 1)=P(Y1=0,Y2=0)+P(Y1=1,Y2=0)+P(Y1=0,Y2=1)

P(Y1=0,Y2=0)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{0}(0.7)^{1-0}=(0.8)^{2}(0.7)=0.448

P(Y1=1,Y2=0)=(2C1)(0.2)^{1}(0.8)^{2-1}(0.3)^{0}(0.7)^{1-0}=2(0.2)(0.8)(0.7)=0.224

P(Y1=0,Y2=1)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{1}(0.7)^{1-1}=(0.8)^{2}(0.3)=0.192

P(Y1+Y2\leq 1)=0.448+0.224+0.192=0.864\\P(Y1+Y2\leq 1)=0.864

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2 years ago
Helpp!!!? need help quick ..
stealth61 [152]
Note that

n^m*n^r=n^(m+r)

2^5*2^x=2^(5+x)

the answer is D
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If f(x) = (xm + 9)2, which statement about f(x) is true?
Marina CMI [18]

Answer:

The correct statement for the given function is:

f(x) is an even function for all even values of m.

Step-by-step explanation:

The correct statement for the given function is:

f(x) is an even function for all even values of m.

The given function(x^m+9)^2 is a quadratic equation. The term Quadratic means the variable gets squared. if m is an even number, that would result also to an even function....

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Eva left her home and drove for 4.3 hours due north at a rate of 60 miles per hour. After visiting a beach, she drove due south
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A regular decagon has sides that are 8 cm long. What is the area of the figure? Round to the nearest whole number.
blsea [12.9K]

<u>Given</u>:

Given that the regular decagon has sides that are 8 cm long.

We need to determine the area of the regular decagon.

<u>Area of the regular decagon:</u>

The area of the regular decagon can be determined using the formula,

A=\frac{s^{2} n}{4 \tan \left(\frac{180}{n}\right)}

where s is the length of the side and n is the number of sides.

Substituting s = 8 and n = 10, we get;

A=\frac{8^{2} \times 10}{4 \tan \left(\frac{180}{10}\right)}

Simplifying, we get;

A=\frac{64 \times 10}{4 (\tan \ 18)}

A=\frac{640}{4 (0.325)}

A=\frac{640}{1.3}

A=642.3

Rounding off to the nearest whole number, we get;

A=642 \ cm^2

Thus, the area of the regular decagon is 642 cm²

Hence, Option B is the correct answer.

5 0
1 year ago
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