Answer:
i think he is 15 i could be wrong
Step-by-step explanation:
Assume that 100% = 45 sales and 35% = X sales amount
You can create a ratio to help you solve for x
45 = 100%
x = 35 %
Which is equal to this fraction: (45/x) = (100/35)
Solving for X by cross multiplying and dividing by 100:
[(45)(35)] / 100 = X = 15.75 = 16 sales (rounded up)
You would need at least 16 sales to increase sales total by 35%
A. -3x+5+7-4x
-3x-4x+5+7
-7x+12
-7x+12-5x+17
-7x-5x+12+17
-12x+29
B. -5*(x+2)= -5x-10
-6x-1+ (-5x-10)= -6x-5x-1-10=
-11x-11
Answer:
The length of side st is 15.
Step-by-step explanation:
A tangent is a straigth line that touches a circle externally at a point on the circumference. Considering one of its properties that tangents from the same point to a fixed point outside a circle are equal.
Then,
/rn/ = /rp/
/tm/ = /tn/
/sm/ = /sp/
But, /rp/ = 7, /rt/ = 17 and /sm/ = 5.
Then,
/rt/ = /rn/ + /tn/
17 = 7 + /tn/ (∵ /rp/ = /rn/ = 7)
⇒ /tn/ = 10
Since /nt/ = 10, then /tm/ = 10 (/tm/ = /nt/)
So that,
/st/ = /sm/ + /tm/
= 5 +10
/st/ = 15
The length of side st is 15.
Answer:
The sample consisting of 64 data values would give a greater precision.
Step-by-step explanation:
The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).
That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.
Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.
The two sample sizes are:
<em>n</em>₁ = 25
<em>n</em>₂ = 64
The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.
Width for n = 25:
Width for n = 64:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B64%7D%7D%3D%5Cfrac%7B1%7D%7B8%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Thus, the sample consisting of 64 data values would give a greater precision