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BigorU [14]
2 years ago
5

Two sides of an obtuse triangle measure 9 inches and 14 inches. The length of longest side is unknown. What is the smallest poss

ible whole-number length of the unknown side? 16 inches 17 inches 24 inches 25 inches
Mathematics
2 answers:
julia-pushkina [17]2 years ago
4 0

Answer:

17 inches

Step-by-step explanation:

An obtuse triangle is the triangle in which one of the side is the longest. It contains an obtuse angle and the longest side is the side that is opposite to the vertex of the obtuse angle.

Let the three sides of the obtuse triangle be a, b and c respectively with c as the longest side. Let a = 9 inches and b = 14 inches.

Now we know that for an obtuse triangle,

$c^2 > a^2 +b^2$

$c^2 > (9)^2 +(14)^2$

$c^2 > 81 +196$

$c^2 > 277$

c > 16.64

Therefore the smallest possible whole number is 17 inches.

True [87]2 years ago
3 0

Answer:

B)17

Step-by-step explanation:

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Ice Cream Scoops - In shops with lots of ice-cream flavors there are many different flavor combinations, even with only a 2-scoo
blondinia [14]

Answer:

The general formula that can be used to find the required combinations for n flavor ice-cream.

N_n = \frac{n(n+1)}{2}

For 10 ice-cream flavors

N_{10} = \frac{10(10+1)}{2}

N_{10} = 55

Step-by-step explanation:

Let V = Vanila, C = Chocolate, S = Strawberry, P = Pineapple, B = Berry

2 ice-cream flavor:

V, C

{V/V, V/C, C/C}

3 possible combinations

3 ice-cream flavor:

V, C, S

{V/V, V/C, V/S, C/S, C/C, S/S}

6 possible combinations

4 ice-cream flavor:

V, C, S, P

{V/V, V/C, V/S, V/P, C/S, C/P, S/P, C/C, S/S, P/P}

10 possible combinations

5 ice-cream flavor:

V, C, S, P, B

{V/V, V/C, V/S, V/P, V/B, C/S, C/P, C/B, S/P, S/B, P/B, C/C, S/S, P/P, B/B }

15 possible combinations

So we have a series of

3, 6, 10, 15...

This series is known as Triangular number series

1 + 2 = 3

1 + 2 + 3 = 6

1 + 2 + 3 + 4 = 10

1 + 2 + 3 + 4 + 5 = 15

The general formula for this series is

N_n = \frac{n(n+1)}{2}

Using the above formula we can predict the number of 2-scoop combinations with 10 flavors.

N_{10} = \frac{10(10+1)}{2}

N_{10} = 55

Therefore, there are 55 different combinations of 2-scoop  with 10 flavors.

5 0
2 years ago
Joseph would like to make 12 pounds of a coffee blend at a cost of $6.25 per pound. He blends Ground Chicory at $4.40 a
zvonat [6]

Answer:

Ground Chicory = 7 pounds and Jamaican Blue Mountain = 5 pounds

Step-by-step explanation:

Joseph would like to make 12 pounds of a coffee blend at a cost of $6.25 per pound.

Total cost of 12 pounds of coffee blend = 6.25 × 12 = $75

Ground Chicory = $4.40 per pound

Jamaican Blue Mountain = $8.84 per pound

Total weight of coffee blend = 12 pounds

Total amount of coffee blend = $75

Let the weight of Chicory be 'x'

The weight of Blue mountain be (12 - x)

75 = 4.40x + 8.84(12-x)

75 = 4.40x + 106.08 + - 8.84x

75 = (4.40x +-8.84x) + 106.08

75 = - 4.44x + 106.08

-4.44x = 75 - 106.08

-4.44x = -31.08

x = 7 pounds

and (12 - x) = 12 - 7 = 5 pounds

Therefore, Ground Chicory would be used 7 pounds and Jamaican Blue Mountain would be used 5 pounds.

7 0
2 years ago
Read 2 more answers
What is the probability of drawing yellow marble followed by a red marble from a bag containing 12 yellow marbles, 16 red marble
boyakko [2]

Option B

Probability of drawing yellow marble followed by a red marble is \frac{32}{301}

<em><u>Solution:</u></em>

Given that a bag containing 12 yellow marbles, 16 red marbles, and 15 green marbles

So total number of marbles = 12 + 16 + 15 = 43

To find: probability of drawing yellow marble followed by a red marble if the first marble is not replaced

<em><u>The probability of an event is given as:</u></em>

probability =\frac{\text { number of favorable outcomes }}{\text { total number of possible outcomes }}$

<em><u>probability of drawing yellow marble followed by a red marble if the first marble is not replaced:</u></em>

First we pick up yellow marble.

Number of favorable outcomes = 12 yellow marbles

Total number of possible outcomes = 43 marbles

\text{ probability} = \frac{12}{43}

Now we have to pick red marble

But first marble is not replaced

So we have 43 - 1 = 42 number of possible outcomes

Favorable outcomes = 16 red marbles

\text{ probability} = \frac{16}{42}

So probability of drawing yellow marble followed by a red marble is:

\text[ probability } = \frac{12}{43} \times \frac{16}{42} = \frac{32}{301}

Thus probability of drawing yellow marble followed by a red marble is \frac{32}{301}

7 0
2 years ago
Let F(x, y, z) = (5ex sin(y))i + (5ex cos(y))j + 7z2k. Evaluate the integral C F · ds, where c(t) = 8 t , t3, exp( t ) , 0 ≤ t ≤
maria [59]

I'm going to assume this reads

\vec F(x,y,z)=5e^x\sin y\,\vec\imath+5e^x\cos y\,\vec\jmath+7z^2\,\vec k

and the path C is parameterized by

\vec c(t)=8t\,\vec\imath+t^3\,\vec\jmath+e^t\,\vec k

with 0\le t\le1. Under this parameterization,

\vec F(x,y,z)=\vec F(x(t),y(t),z(t))=5e^{8t}\sin(t^3)\,\vec\imath+5e^{8t}\cos(t^3)\,\vec\jmath+7e^{2t}\,\vec k

and

\mathrm d\vec c=\dfrac{\mathrm d\vec c}{\mathrm dt}\,\mathrm dt=(8\,\vec\imath+3t^2\,\vec\jmath+e^t\,\vec k)\,\mathrm dt

Then in the integral,

\displaystyle\int_C\vec F\cdot\mathrm d\vec s=\int_0^1\vec F(x(t),y(t),z(t))\cdot\frac{\mathrm d\vec c}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^1(7e^{3t}+15e^{8t}t^2\cos(t^3)+40e^{8t}\sin(t^3))\,\mathrm dt\approx\boxed{12586.5}

(It's unlikely that an exact answer can be found in terms of elementary functions)

4 0
2 years ago
Renna pushes the elevator button, but the elevator does not move. The mass limit for the elevator is 450 kilograms (kg), but Ren
liraira [26]

The picture below has both of the answers to your problem.

7 0
2 years ago
Read 2 more answers
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