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Blababa [14]
2 years ago
12

Mario walked at a rate of 2/3 miles every 10 minutes what is his unit rate every mile per hour

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
5 0

Mario's unit rate is given by 900 miles/hour.

Explanation:

We have been given that Mario walked at a rate of 2/3 miles every 10 minutes.

We have the relation between speed, time and distance, which is given by

\text{Speed}= \frac{\text{Distance}}{\text{Time}}

We have,

Distance = \frac{2}{3} \text{ miles}

Time = 10 minutes

On substituting these values in the above formula, we get

\text{Speed} = \frac{2/3}{10}\\\\ \text{Speed} =\frac{2}{10\cdot 3}\\\\ \text{Speed} =[tex]\frac{1}{15} \text{ miles/min}[/tex]

We have to find the unit rate in mile per hour, so we need to multiply it by 60

Thus, unit rate is given by

\frac{1}{15} \times 60\\ = 4 \text{ miles/hour}

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ΔEFG ~ ΔLMN. Find LM.
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EFG ~ LMN, if EF ~ LM, then whatever the number is for EF times whatever the others are multiplied by, you will get LM
for example: 

FG (10) ~ MN (20)

if EF is (5), then LM is (10) (for you are multiplying by two.

Another example:

if FG is (100) ~ MN will be (200) (again for you are multiplying by two.

hope this helps 
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2 years ago
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What is the relative frequency of the revenue earned by B&B Motors from sales of mini trucks compared to the total sales rev
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Answer: 0.46

Step-by-step explanation: B&B motors convertible - 0.59 all four companies - 0.39 mini trucks- 0.13 .59-0.13=0.46

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Find a single expression that represents the area of the outer ring of the circle if the area of the whole circle is represented
sp2606 [1]

Answer:  The answer is A_o=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.


Step-by-step explanation: Given that the area of the whole circle is represented by the expression

A_c=25x^2-12x-9.

We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.

Now, if 'r' represents the radius of the circle, then we have

A_c=\pi r^2\\\\\Rightarrow \dfrac{22}{7}r^2=25x^2-12x-9\\\\ \Rightarrow r^2=\dfrac{7}{22}(25x^2-12x-9)\\\\\Rightarrow r=\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.

Thus, the area of the outer ring is

A_o=2\pi r=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.


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2 years ago
A ball is drawn at random from a container that holds 8 yellow balls numbered 1 to 8, 6 orange balls numbered 1 to 6, and 10 gra
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A)

total of balls = 8+6+10= 24 balls 

3/24= .125 and it is 12.5 % that one of the orange balls is 5 because it is an odd number.

B) 

4/24 =.167 0r 16.7% that of the gray balls is numbered 8.


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2 years ago
In the diagram, transversal t cuts across the parallel lines a and b. Match the pairs of angles with the relationship that shows
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we know that

<u>case a)</u> alternate exterior angles

m∠2=m∠7 --------> by alternate exterior angles

m∠1=m∠8 --------> by alternate exterior angles

<u>case b)</u> alternate interior angles

m∠3=m∠6 --------> by alternate interior angles

m∠5=m∠4 --------> by alternate interior angles

<u>case c)</u> corresponding angles

m∠1=m∠5 --------> by corresponding angles

m∠3=m∠7 --------> by corresponding angles

m∠2=m∠6 --------> by corresponding angles

m∠4=m∠8 --------> by corresponding angles

<u>case d)</u> vertical angles

m∠1=m∠4 --------> by vertical angles

m∠2=m∠3 --------> by vertical angles

m∠5=m∠8 --------> by vertical angles

m∠6=m∠7 --------> by vertical angles

therefore

the answer in the attached figure

5 0
2 years ago
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