All categories

2 years ago

Mario walked at a rate of 2/3 miles every 10 minutes what is his unit rate every mile per hour

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

5 0

Mario's unit rate is given by 900 miles/hour.

Explanation:

We have been given that Mario walked at a rate of 2/3 miles every 10 minutes.

We have the relation between speed, time and distance, which is given by

$\text{Speed}= \frac{\text{Distance}}{\text{Time}}$

We have,

Distance = $\frac{2}{3} \text{ miles}$

Time = 10 minutes

On substituting these values in the above formula, we get

$\text{Speed} = \frac{2/3}{10}\\\\ \text{Speed} =\frac{2}{10\cdot 3}\\\\ \text{Speed} =[tex]\frac{1}{15}$ \text{ miles/min}[/tex]

We have to find the unit rate in mile per hour, so we need to multiply it by 60

Thus, unit rate is given by

$\frac{1}{15} \times 60\\ = 4 \text{ miles/hour}$

You might be interested in

The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c

boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

$p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!}$ for x = 0, 1, 2, ...

where $\lambda$ , the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is $1.2 \cdot 3 =3.6$

The probability of exactly three flaws in 150 m of cable is

$P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246$

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is $1.2 \cdot 2 =2.4$

$P(X\geq 2)=1-P(X$

$P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155$

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is

$P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143$

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

$(0.36143)(0.36143) = 0.13063$

4 0

2 years ago

Working alone, Elisa can sweep a porch in 11 minutes. Pranav can sweep the same porch in 13 minutes. How long would it take if t

GaryK [48]

Elisa, e = 11mins

Prenav,p = 13mins

time to complete, t

1 = t( 1/11 + 1/13) = t (24/143)

t = 143/24 = 5.96min

Answer is A 5.96mins

5 0

2 years ago

How do you find parametric equation for line with slope -2, passing through the point P(-10, -20)?

olga_2 [115]

Y=-2x-40 will be equation

8 0

2 years ago

Estimate 58% of 121 by using 10%

kvv77 [185]

58% is about equal to 60%, 10% of 121 is 12.1.
12.1 * 6 = 72.6
To take this further, 58% is 2% less than 60%, or 2 times 1%. 1% of 121 is 1.21.
72.6 - (1.21 * 2) = 72.6 - 2.42 = 70.18

5 0

2 years ago

The cost of playing pool increases with the amount of time using the table. Identify the independent and dependent quantity in t

Marina CMI [18]

The cost is dependent on the time played because the cost and go up without the time going up

3 0

2 years ago

Read 2 more answers