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2 years ago

9

. A high school currently has a 30% dropout rate. They’ve been tasked to decrease that rate by 20%. Find the equivalent percenta

ge point drop.

1 answer:

Crazy boy [7]2 years ago

3 0

Answer:

The equivalent percentage point drop = 10%

Step-by-step explanation:

The percentage point change is the difference between the final and initial values.

The percentage change is the difference between the final and initial values

divided by the initial value

It is required to decrease the dropout rate from 30% to 20%

The point change = 20 - 30 = -10 (-ve change ⇒ decrease)

The percentage change = $\frac{10}{30}*100 = 33.33_%$ %

So, the equivalent percentage point drop = <u>10%</u>

And the percentage change = <u>33.33%</u>

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Answer and Step-by-step explanation:

Data provided in the question

Mean = 1.1 hours per call =

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Based on the above information

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And, there is 8 hours per day

So, it would be

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Answer:

a

The Null hypothesis represented as

$H_0: \mu_1 - \mu_2 = 0$

The Alternative hypothesis represented as

$H_a: \mu_1 - \mu_2 < 0$

b

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c

There is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students

Step-by-step explanation:

From the question we are told that

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The sample mean for graduates is $\= x _1 = 148$

The sample standard deviation for graduates is $\sigma_1 = 16$

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The sample mean for under-graduates is $\= x _2 = 153$

The sample standard deviation for graduates is $\sigma_2 = 21$

The Null hypothesis represented as

$H_0: \mu_1 - \mu_2 = 0$

The Alternative hypothesis represented as

$H_a: \mu_1 - \mu_2 < 0$

Where $\mu_1 \ and \ \mu_2$ are the population mean

Now the test statistic is mathematically represented as

$t = \frac{(\= x_1 - \= x_2 ) }{ \sqrt{ \frac{ (n_1 - 1 )\sigma_1 ^2 + (n_2 - 1)\sigma_2^2}{n_1 +n_2 -2} } * \sqrt{ \frac{1}{n_1} + \frac{1}{n_2} } }$

substituting values

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The above answer is gotten using a p-value calculator at (0.05) level of significance

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