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Greeley [361]
2 years ago
14

Decide whether the following situation is looking for the percent, the part, or the whole:The 14 compact cars sold by a dealer o

n Monday was 56% of the cars sold that day.
Mathematics
1 answer:
borishaifa [10]2 years ago
6 0

Answer:

  whole

Step-by-step explanation:

No question is posed.

If we assume we're interested in the number of cars sold on Monday, we have ...

  part = percent × whole

  14 = 56% × whole

It would seem that we're looking for the whole.

__

14/.56 = 25 cars were sold on Monday.

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Suppose abby tracks her travel time to work for 60 days and determines that her mean travel time, in minutes, is 35.6. assume th
HACTEHA [7]
Given that:
mean,μ=35.6 min
std deviation,σ=10.3 min
we are required to find the value of x such that 22.96% of the 60 days have a travel time that is at least x.
using z-table, the z-score that will give us 0.2296 is:-1.99
therefore:
z-score is given by:
(x-μ)/σ
hence:
-1.99=(x-35.6)/10.3
-20.497=x-35.6
x=35.6-20.497
x=15.103


7 0
2 years ago
Read 2 more answers
Jack bought 4 dozen eggs at $10 per dozen. 6 were broken. what percent of his money goes to waste
Korvikt [17]

So, if he has 4 dozen eggs, ten dollars per dozen, he has spent $40 on 48 eggs. <em>This means the cost of one egg = 48/40. </em>This can simplify to <em>6/5 </em>which is equal to<em> $1.20. </em>This means the value of one egg is $1.20, including the broken ones! So if six were broken, we multiply 1.20 x 6 which equals <em>$7.20!</em>

Use this "formula" to help find percentages

<em>Part/Total = %( Percentage )/ 100</em>

Now that we know how much money has gone to waste, we can plug in the known values into this "formula."

<em>7.2/48 = x/100</em>

Solve accordingly; cross multiply, 720 = 48x; divide both sides of the equation by 48 to isolate the variable, 720/48 = 48x/48; now you have your final answer which is:

15 = x; going back to the "formula" this means 15% of his money has gone to waste. I hope this helped! :)

5 0
2 years ago
Christian is rewriting an expression of the form y = ax2 + bx + c in the form y = a(x – h)2 + k. Which of the following must be
Shkiper50 [21]

Answer:

The Value Remains the Same

Step-by-step explanation:

Trust

7 0
1 year ago
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You are traveling down a country road at a rate of 95 feet/sec when you see a large cow 300 feet in front of you and directly in
emmainna [20.7K]

Answer:

1) You can rely solely on your brakes because when doing so the car will just travel 250ft from the point you hit your brakes till the point the car stopped completely, leaving you 50ft away from the cow.

2) See attached picture.

j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet

j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.

j"(t) represents the acceleration of the car t seconds after the brakes have been hit in ft/s^{2}

3) yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.

4) j(t)=\left \{ {{95t-9t^{2}; 0\le t

j'(t)=\left \{ {{95-18t; 0\leq t

(see attached picture for graph)

Step-by-step explanation:

1) In this part of the problem we need to find the time when the speed of the car is 0. Gets to a complete stop. For this we will need to take the derivative of the position function so we get:

j(t)=95t-9t^2

j'(t)=95-18t

and we set the first derivative equal to zero so we get:

95-18t=0

and solve for t

-18t=-95

t=\frac{95}{18}

t=5.28s

so now we calculate the position of the car after 5.28 seconds, so we get:

j(5.28)=95(5.28)-9(5.28)^{2}

j(5.28)=250.69ft

so we have that the car will stop 250.69ft after he hit the brakes, so there will be about 50ft between the car and the cow when the car stops completely, so he can rely just on the breaks.

2) For answer 2 I take the second derivative of the function so I get:

j(t)=95t-9t^{2}

j'(t)=95-18t

j"(t)=-18

and then we graph them. (See attached picture)

j(t) represents the distance from the point you hit the brake t seconds after you hit it in feet

j'(t) represents the velocity of the car t seconds after the brakes have been hit in ft/s.

j"(t) represents the acceleration of the car t seconds after the brakes have been hit in ft/s^{2}

3)  yes, any time after t=5.28 will not accurately model the path of the car since at that exact time the car will reach a velocity of 0ft/s and unless another force is applied to the car, then the car will not move after that time.

4) j(t)=\left \{ {{95t-9t^{2}; 0\le t

j'(t)=\left \{ {{95-18t; 0\leq t

(see attached picture for graph)

5 0
2 years ago
A right cylinder has a radius of 2 units and height of 5 units.What is the volume of the cylinder? Round to the nearest tenth.
UkoKoshka [18]
V=hpir^2
r=2
h=5
pi≈3.141592

v=5*3.141592*2^2
v=5*3.141592*4
v=20*3.141592
v=62.83185307179586476925286766559
round to tenth
62.8 cubic units
8 0
2 years ago
Read 2 more answers
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