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Dima020 [189]
2 years ago
14

Solve for x in the equation x squared + 11 x + StartFraction 121 Over 4 EndFraction = StartFraction 125 Over 4 EndFraction.

Mathematics
2 answers:
Solnce55 [7]2 years ago
8 0

Answer:

the answer is x=-11/2 +or- 5 (rooted)5/2

AKA D

Step-by-step explanation:

Ira Lisetskai [31]2 years ago
6 0

Answer:

Below

Step-by-step explanation:

● x^2 + 11x + 121/4 = 125/4

Substract 125/4 from both sides:

● x^2 + 11x + 121/4-125/4= 125/4 -125/4

● x^2 + 11x - (-4/4) = 0

● x^2 +11x -(-1) = 0

● x^2 + 11 x + 1 = 0

This is a quadratic equation so we will use the determinanant (b^2-4ac)

● a = 1

● b = 11

● c = 1

● b^2-4ac = 11^2-4*1*1 = 117

So this equation has two solutions:

● x = (-b -/+ √(b^2-4ac) ) / 2a

● x = (-11 -/+ √(117) ) / 2

● x = (-11 -/+ 3√(13))/ 2

● x = -0.91 or x = -10.9

Round to the nearest unit

● x = -1 or x = -11

The solutions are { -1,-11}

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Anita is a door-to-door saleswoman for a company selling bedcovers. The company pays her a fixed salary of Rs W every month and
lorasvet [3.4K]

Given:

Anita's fixed salary = Rs. W

Bonus = Rs. Z for every bedcover sold by her.

To find:

Her total earnings if she sold 46 bedcovers.

Solution:

We have,

Bonus if she sold 1 bedcover = Rs. Z

Bonus if she sold 46 bedcover = Rs. Z × 46

We know that,

Total earnings = Fixed salary + Bonus

                        = W+Z\times 46

Therefore, the correct option is (b).

3 0
1 year ago
The quality control manager at a light bulb factory needs to estimate the mean life of a batch (population) of light bulbs. We a
Nadusha1986 [10]

Answer:

<em>a)95%  confidence intervals for the population mean of light bulbs in this batch</em>

(325.5 ,374.5)

b)

<em>The calculated value Z = 4 > 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The manufacturer has not right to take the average life of the light bulbs is 400 hours.</em>

Step-by-step explanation:

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

The tabulated value Z₀.₉₅ = 1.96

<em>95%  confidence intervals for the population mean of light bulbs in this batch</em>

<em></em>(x^{-} - Z_{\frac{\alpha }{2} } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\frac{\alpha }{2} }\frac{S.D}{\sqrt{n} } )<em></em>

<em></em>(350 - 1.96\frac{100}{\sqrt{64} } , 350 + 1.96\frac{100}{\sqrt{64} } )<em></em>

(350 -24.5, 350 +24.5)

(325.5 ,374.5)

b)

<u><em>Explanation</em></u>:-

Given mean of the Population μ = 400

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

<u><em>Null hypothesis</em></u> : H₀:The manufacturer has right to take the average life of the light bulbs is 400 hours.

μ = 400

<u><em>Alternative Hypothesis: H₁:</em></u> μ ≠400

<u><em>The test statistic </em></u>

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

Z = \frac{350 -400}{\frac{100}{\sqrt{64} } }

|Z| = |-4|

The tabulated value   Z₀.₉₅ = 1.96

The calculated value Z = 4 > 1.96 at 0.05 level of significance

Null hypothesis is rejected.

<u><em>Conclusion:</em></u>-

The manufacturer has not right to take the average life of the light bulbs is 400 hours.

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2 years ago
A small cube with side length 6y is placed inside a larger cube with side length 4x^2. What is the difference in the volume of t
fomenos

the different volume is the numbers. 4*2*6=?


3 0
2 years ago
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Before a new video game is released, it is tested by a number of volunteer gamers. During testing, the experimental probability
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Answer:

2000 players will complete the game with a perfect score.

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This means 1 out of 500 people will be able to finish with perfect score.

Now,

the game is given to 1,000,000 (1 million) people and how much do we expect to finish with perfect score?? Simple! It would be  \frac{1}{500}the of 1 million!

We do the calculation shown below:

\frac{1}{500}*1,000,000=2000

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2 years ago
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Answer:

87.5% percent chance.

Trust me it's right.

6 0
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