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Klio2033 [76]
2 years ago
13

How many weeks of flea treatment would Jim’s dog get from one package if each treatment only lasted 3 weeks In a normal year whe

n a flea treatment last 4 weeks how many more weeks of treatment would Jim’s dog get from one package. Each flea treatment usually last for about 4 weeks but one year the fleas were especially bad Jim’s dog needed to be treated for fleas every 3 weeks until the weather cooled off
Mathematics
1 answer:
4vir4ik [10]2 years ago
4 0

Solution

Number of weeks in a year = 52 weeks

If in a normal year when each package of flea treatment lasts for 4 weeks, then in a year there Jim's dog will have to be treated for

\frac{52}{4} =13 times

Where as, when the fleas are bad in a year, the treatment lasts for only 3 weeks.

Then in a year Jim's dog would get

\frac{52}{3} =17 times


So Jim's dog will get 17- 13 =4 treatments more.

4 treatments that are made in 3 weeks each will be 4×3 =12 weeks more treatment

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This list shows the age at which 43 U.S. Presidents began their terms. 57 61 50 54 54 54 56 54 61 54 48 49 42 51 61 57 68 65 50
tamaranim1 [39]

Answer:

B) 54

Step-by-step explanation:

A mode of a number set is the number the appears the most.

In the list given, 54 was the number that appeared the most.

8 0
2 years ago
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I WILL AWARD BRAINLIEST!! PLEASE HELP!!! The figure below shows the movement of a pedestrian from point B to point E. Using the
MissTica

A) The speed of the pedestrian BC is 5 km/h

    The speed of the pedestrian CD is 0 km/h

    The speed of the pedestrian DE is 5 km/h

B) He arrived E since the stop after 6 hours

C) The formula for section BC is d(t) = 40 - 5t

    The formula for section CD is d(t) = 20

    The formula for section DE is d(t) = 50 - 5t

Step-by-step explanation:

A)

In the time-distance graph the speed is the rate of change of distance

and that mean speed = Δd/Δt ⇒ (slope of the line)

In line BC:

1. Δd = 40 - 20 = 20 km

2. Δt = 4 - 0 = 4 hours

3. The speed = 20 ÷ 4 = 5 km/h

The speed of the pedestrian BC is 5 km/h

In line CD:

1. Δd = 20 - 20 = 0 km

2. Δt = 6 - 4 = 2 hours

3. The speed = 0 ÷ 2 = 0 km/h

The speed of the pedestrian CD is 0 km/h

In line DE:

1. Δd = 20 - 0 = 20 km

2. Δt = 10 - 6 = 4 hours

3. The speed = 20 ÷ 4 = 5 km/h

The speed of the pedestrian DE is 5 km/h

B)

∵ He stop at t = 4 hours

∵ He arrived at point E at t = 10 hours

∵ 10 - 4 = 6 hours

He arrived E since the stop after 6 hours

C)

The speeds are represented by lines

The form of the equation of a line is f(x) = mx + c, where m represents

the slope of the line and c is the y-intercept (y when x = 0)

1. f(x) is d(t)

2. m is the speed

3. x is t

4. You can find c by substitute d and t by any point on the line

Line BC

Line BC has negative slope because d decreases when t increases

∵ m = -5 and c = 40

∴ d(t) = 40 - 5t

The formula for section BC is d(t) = 40 - 5t

Line CD

Line CD is a horizontal line (equation any horizontal line is y = c)

∴ m = 0 and c = 20

∴ d(t) = 20

The formula for section CD is d(t) = 20

Line DE

Line DE has negative slope because d decreases when t increases

∵ m = -5

∴ d(t) = -5t + c

To find c substitute the coordinates of point D in the equation

∵ The coordinates of point D are (6 , 20)

∴ 20 = -5(6) + c

∴ 20 = -30 + c

Add 30 to both sides

∴ c = 50

∴ d(t) = 50 - 5t

The formula for section DE is d(t) = 50 - 5t

Learn more:

You can learn more about the distance, speed, and time in

brainly.com/question/5102020

#LearnwithBrainly

3 0
2 years ago
Harper has $15.00 to spend at her grocery store. She is going to buy bags of fruit that cost $4.75 each and one box of crackers
Andrej [43]
First write the inequality:    15\leq4.75x +3.50

Then to solve, first subtract 3.50 from both sides to get:

11.50\leq4.75x

Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag  of fruit, you round down. So your final answer would be 2 bags of fruit.
7 0
2 years ago
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A ball is thrown from a height of 43 meters
AveGali [126]
When the ball will hit the ground, the height will be zero. So we need to replace h with 0 in our equation, and solve for t:
0=43-4t-5t^{2}
-5t^{2}-4t+43=0
To solve this equation we are going to use the quadratic formula: t= \frac{-b(+/-) \sqrt{b^{2}-4ac} }{2a}.
From our height equation, we can infer that a=-5, b=-4, and c=43. So lets replace those values in our quadratic formula to find t
t= \frac{-(-4)(+/-) \sqrt{(-4)^{2}-4(-5)(43)} }{2(-5)}
t=- \frac{5}{8} - \frac{ \sqrt{713} }{8} or t=- \frac{5}{8} + \frac{ \sqrt{713} }{8}
t=-3.96 or t=2.71
Since time cannot be negative, t=2.71 is the solution of our equation.

We can conclude that the ball will hit the ground after 2.71 seconds.
4 0
2 years ago
a student concluded that the solution to the equation sqrt 2x+1+3=0 is x=4 Do you agree? Explain why or why not.
Lina20 [59]

Answer:

  No.

Step-by-step explanation:

We assume you're concerned with

  \sqrt{2x+1}+3=0

The sum of a non-negative number and a positive number cannot be zero. The square root is always non-negative.


6 0
2 years ago
Read 2 more answers
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