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cestrela7 [59]
2 years ago
6

The statement below describes a situation in which opposite quantities combine to make 0. Is the statement true or false? A plan

e takes off, circles the airport, then lands at the same airport
Mathematics
2 answers:
Nadusha1986 [10]2 years ago
5 0
I believe this is true....lets say the plane takes off and goes up 500 ft.....it circles, but then it has to come back down...land...so it comes down 500 ft...
500 - 500 = 0
Romashka-Z-Leto [24]2 years ago
4 0

Answer:

was it true or false

Step-by-step explanation:

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For ΔABC, ∠A = 4x - 10, ∠B = 5x + 10, and ∠C = 7x + 20. If ΔABC undergoes a dilation by a scale factor of 1 3 to create ΔA'B'C'
VLD [36.1K]
We know that the angles of a triangle sum to 180°.  For ΔABC, this means we have:
(4x-10)+(5x+10)+(7x+20)=180

Combining like terms,
16x+20=180

Subtracting 20 from both sides:
16x=160

Dividing both sides by 16:
x=10
This means ∠A=4*10-10=40-10=30°; ∠B=5*10+10=50+10=60°; and ∠C=7*10+20=70+20=90.

For ΔA'B'C', we have
(2x+10)+(8x-20)+(10x-10)=180

Combining like terms, 
20x-20=180

Adding 20 to both sides:
20x=200

Dividing both sides by 20:
x=10

This gives us ∠A'=2*10+10=20+10=30°; ∠B'=8*10-20=80-20=60°; and ∠C'=10*10-10=100-10=90°.

Since the angle are all congruent, ΔABC~ΔA'B'C' by AAA.
5 0
2 years ago
Read 2 more answers
The geometric average of -12%, 20%, and 25% is _________.
Grace [21]
<span>20.28% is the answer</span>
8 0
2 years ago
Triangle H N K is shown. Angle H N K is 90 degrees. The length of hypotenuse H K is n, the length of H N is 12, and the length o
Mazyrski [523]

Answer:

13

Step-by-step explanation:

From the question, we are given a triangle HNK with an angle of 90°

The length of hypotenuse H K is n,

the length of HN is 12

the length of N K is 6.

From the above values, obtained in the question, we can see that this is a right angled triangle.

We are asked to find the length of the hypotenuse.

We can use Pythagoras Theorem of solve for this.

c² = a² + b²

where c = HK = n

a = NK = 6

b = HN = 12

c² = 6² + 12²

c² = 36 + 144

c² = 180

c = √180

c = 13.416407865

Approximately to the nearest whole number = 13

Therefore the value of HK = n = 13

We can also use Law of Cosines as given in the question to solve for this.

a² = b² + c² - 2ac × Cos A

where c = HK = n

a = NK = 6

b = HN = 12

Hence

c² = a² + b² - 2ab × Cos C

c = √ (a² + b² - 2ab × Cos C)

Where C = 90

c = √ 6² + 12² - 2 × 6 × 12 × Cos 90

c = 13.42

Approximately to the nearest whole number ≈ 13

Therefore the value of HK = n = 13

8 0
2 years ago
Margie received her store order on 12/3/16 at 4AM. She just opened one of the fountain BIBs today, 12/7/16 at 12PM. The BIB has
Korolek [52]

Answer:

It’s a trick question all you need is the two dates that’s it

Step-by-step explanation:

8 0
2 years ago
Tony has $20. He wants to buy at least 4
zavuch27 [327]

Tony has $20. He wants to buy at least 4

snacks. Hot dogs (x) are $3 each.

Peanuts (y) are $2 each.​

Answer:

To solve the above question, we use the below inequality equations

x + y ≥ 4 snacks .........Inequality equation 1

3x + 2y ≤ $20 ..........Inequality equation 2

Step-by-step explanation:

We can make use of the inequality equations

Hot dogs = (x) are $3 each.

Peanuts = (y) are $2 each.​

He wants to buy at least 4

x + y ≥ 4 snacks .........Inequality equation 1

3x + 2y ≤ $20 ..........Inequality equation 2

From the above inequality equations, Tony can buy at least 4 snacks but he can only spend $20.

Let take a random number, where x = 4, and y = 4. This means Tony can buy

a) 4($3) + 4($2) = 12 + 8 = $20

The total number of snacks = 4 + 4 = 8 snacks.

b)

This answer above confirms the inequality equations 1 and 2

x + y ≥ 4 snacks .........Inequality equation 1

8 snacks ≥ 4 snacks

3x + 2y ≤ $20 ..........Inequality equation 2

$20 ≤ $20

6 0
2 years ago
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