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2 years ago

11

it says priya's family exchanged 250 dollars for 4,250 pesos. Riya bought a sweater for 510 pesos. how many did the sweater cost

?

2 answers:

White raven [17]2 years ago

8 0

Answer:

30.

Step-by-step explanation:

AfilCa [17]2 years ago

6 0

It says priya's family exchanged 250 dollars for 4,250 pesos. Riya bought a sweater for 510 pesos. how many did the sweater cost?

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One factor of the polynomial 2x^3 - 3x^2 - 3x + 2 is ( x - 2 ). Which expression represents the other factor, or factors, of the

Georgia [21]

Answer:

Option (D)

Step-by-step explanation:

Given polynomial is,

2x³ - 3x² - 3x + 2

If (x - 2) is the factor of the given polynomial,

By synthetic division we can get the other factor.

2 | 2 -3 -3 2

<u> 4 2 -2 </u>

2 1 -1 0

Therefore, other factor of the given polynomial is (2x² + x - 1)

Now (2x² + x - 1) = 2x² + 2x - x - 1

= 2x(x + 1) -1(x + 1)

= (2x - 1)(x + 1)

Therefore, factors of the given polynomial other than (x - 2) are (2x - 1) and (x + 1)

Option (D) will be the answer.

4 0

2 years ago

A community hall is in the shape of a cuboid the hall is 40m long 15m high and 3m wide. 10 litre paint covers 25m squared costs

Darina [25.2K]

Answer:

Total cost for tiles and paints is $924.

Step-by-step explanation:

We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.

The paint will be required for 4 walls and ceiling.

Let us find area of walls and ceiling.

$\text{Area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)$

$\text{Area of walls and ceiling}=1200+90+120$

$\text{Area of walls and ceiling}=1410$

Therefore, the area of walls and ceiling is 1410 square meters.

Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,

$\text{ The total painting cost}=10*(\frac{1410}{25})$

$\text{ The total painting cost}=10*56.4=564$

Therefore, the total painting cost is $564.

Tiles will be required for floor. Let us find the area of floor.

$\text{Area of floor} = 40*3\text{ square meters}$

$\text{Area of floor} =120\text{ square meters}$

Given: 1m squared floor tiles costs $3. So,

$\text{Total cost for tiles} = 3*120 = 360$

Therefore, the total tiles cost is $360.

Now let us find combined total cost of tiles and paint.

$\text{Combined total cost}= 564+360 = 924$

Therefore, the combined total cost of tiles and paint is $924.

6 0

2 years ago

If five friends want to share 1.25 of a pizza evenly how much pizza would each person get

Amanda [17]

1.25 /5

12/5 = 2 with 2 left over

25/5 = 5

2 numbers

1.25 /5 = .25

Each person gets .25 of a pizza

4 0

2 years ago

Read 2 more answers

Jackson is conducting an experiment for his Physics class. He attaches a weight to the bottom of a metal spring. He then pulls t

olga55 [171]

We have that the spring is going to have a sin or a cos equation. We have that the maximum distance of the spring is 6 inches and it is achieved at t=0. Let's fix this as the positive edge. Until now, we have that the function is of the form:
6sin(at+B). We have that the period is 4 minutes and hence that the time component in the equation needs to make a period (2pi) in 4 minutes. Thus 4min*a=2p, a=2p/4=pi/2. In general, a=2pi/T where a is this coefficient, T is the period. Finally, for B, since sin(pi/2)=1, we have that B=pi/2 because when t=0, we have that 6sin(B)=6. Substituting, we have f(t)=6sin(pi*t/2+pi/2)=6cos(pi*t/2)
by trigonometric identities.

7 0

2 years ago

Read 2 more answers

On her first day in a hospital, Kiri receives u1 milligrams (mg) of a therapeutic drug. The amount of the drug Kiri receives inc

Valentin [98]

Answer:

a. 21 = u1 + 6·d

b. 29 = u1 + 10·d

c. d = 2, u1 = 9

Step-by-step explanation:

a. The given parameters are;

The amount of therapeutic drug Kiri receives on her first at the hospital = u1 milligrams

The amount of drug increase received by Kiri each day = d

The amount of drug Kiri received on the seventh day = 21 mg

The amount of drug she received on the eleventh day = 29 mg

Therefore, we have an arithmetic progression with the formula for the nth term given as follows;

aₙ = a₁ + (n - 1)·d

Where;

a₁ = u1

n = The number of terms

Therefore, for the 7th day, the amount of drugs she receives, which is 21 milligrams, is given as follows;

a₇ = u1 + (7 - 1)·d = u1 + 6·d = 21

The equation for the amount of drugs she receives in terms of u1 and d on the seventh day is given as follows;

21 = u1 + 6·d

b. For the eleventh day, the amount of drugs she receives, which is 29 milligrams, is given as follows;

a₁₁ = u1 + (11 - 1)·d = u1 + 10·d = 29

Therefore, the equation for the amount of drugs she receives in terms of u1 and d on the eleventh day is given as follows;

29 = u1 + 10·d

c. Therefore, we have two equations which are given as follows;

21 = u1 + 6·d................(1)

29 = u1 + 10·d..............(2)

Subtracting equation (1) from equation (2) gives;

29 - 21 = (u1 + 10·d) - (u1 + 6·d)

8 = 4·d

d = 8/4 = 2

d = 2

From equation (1), we have;

21 = u1 + 6·d = u1 + 6×2 = u1 + 12

21 = u1 + 12

21 - 12 = u1

∴ u1 = 9

d = 2, u1 = 9.

4 0

2 years ago