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-Dominant- [34]
1 year ago
7

A gallon of stain is enough to cover 200 square feet of decking. Bradley has two areas of decking he would like to cover with st

ain. One rectangular area is 23 feet by 10.4 feet, and the other is 10.5 feet by 7.2 feet. Which expression gives the number of gallons of stain Bradley will need?
Mathematics
2 answers:
Margaret [11]1 year ago
4 0
He needs at least 2 gallons of the stain; though he will not use all of the second gallon
Liula [17]1 year ago
4 0

Answer:   \frac{23\times 10.4 +10.5\times 7.2}{200}  gallon

Step-by-step explanation:

A gallon of stain is enough to cover 200 square feet of decking.

⇒The quantity of stain is enough to cover 1 square feet = \frac{1}{200} gallon.

Now, the total area of decking = Rectangle having the dimension 23 × 10.4 + Rectangle having the dimension 10.5 × 7.2

= ( 23 × 10.4 + 10.5 × 7.2 ) feet^2

⇒ The quantity of stain is enough to cover 1 square feet = \frac{23\times 10.4 +10.5\times 7.2}{200}  gallon

=  \frac{314.8}{200}

= 1.574 gallon.



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The number of people that enter a drugstore in a given hour is a Poisson random variable with parameter λ = 10. Compute the cond
Nonamiya [84]

Answer:

The probability is 0.2650

Step-by-step explanation:

Let's start assuming that men and women come in at the same rate.

Let's define the following random variables :

X : ''Number of people that enter a drugstore''

M : ''Number of men that enter a drugstore''

W : ''Number of women that enter a drugstore''

The number of people will be the number of men plus the number of women

⇒

X = M + W

We are also assuming that M and W are independent random variables.

X ~ Po (10)

M ~ Po (λ1)

W ~ Po (λ2)

λ1 = λ2 because we assumed that men and women come in at the same rate.

λ1 = λ2 = λ

λ1 + λ2 = λ + λ ⇒ 2λ = 10 ⇒ λ = 5

M ~ Po (5)

W ~ Po (5)

Because X is the sum of two independent Poisson random variables.

We are looking for :

P(M\leq 3/W=10)=P(M\leq 3)

Because we assume independence.

P(M\leq 3)= P(M=0)+P(M=1)+P(M=2)+P(M=3)

P(M=m)=\frac{5^{m}}{m!}e^{-5} because is a Poisson random variable with λ = 5

P(M\leq 3)=\frac{5^{0}}{0!}e^{-5}+\frac{5^{1}}{1!}e^{-5}+\frac{5^{2}}{2!}e^{-5}}+\frac{5^{3}}{3!}e^{-5}

P(M\leq 3)=e^{-5}+5e^{-5} +(\frac{25}{2})e^{-5} +\frac{125}{6}e^{-5}=0.2650

P(M\leq 3)=0.2650

5 0
2 years ago
Lana draws a triangle( LMN) on the coordinate plane. What is the perimeter of the triangle( LMN)? Round to the nearest unit.
Dmitriy789 [7]

Answer:

25

Step-by-step explanation:

The longest side is 12.

The two other sides of the triangle=\sqrt{3 squared+6 squared}=(9+36)square rooted=45 square rooted is about 6.7.

6.7*2=13.4

13.4+12=25.4

25.4 rounded to the nearest unit is 25.

8 0
2 years ago
Zachary is buying 4 tires for his car. The table shows the prices and the advertised sales for the same type of tire at 4 tire s
balandron [24]

Answer:

prolly r

Step-by-step explanation:

I guessed bc this looks really hard n borin

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2 years ago
Find the following measure for this figure. Lateral area = 24 square units 48 square units 96 square units
Savatey [412]
We are asked to solve for the lateral surface area of the cylinder such that the formula that we can used is Lateral Surface Area = 2pi*r*h where "r" represents the radius of the cylinder and "h" represents the height of the cylinder. In this problem, we are given with the following values:
r = 4 inches
h = inches
Solving for the lateral surface area, we have it:
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The answer is 48pi unit2.
8 0
2 years ago
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The same student (as in the previous question) realizes that he has forgotten to zero the balance before measurements of data se
seraphim [82]

Answer:

The average value of the second set of measurements obtained with the properly zeroed balance is 550g.

Step-by-step explanation:

The average value of a set is the sum of all the elements of the set divided by the cardinality(number of elements) of the set.

Here, our set of data with the properly zeroed balance is as follows:

547 g, 554 g, 546 g, 554 g, 548 g, 545 g, 546 g, 555 g, 553 g, 552

There are 10 values in this set, to the average value is:

A = \frac{547 g + 554 g + 546 + 554 g + 548 g + 545 g + 546 g + 555 g + 553 g + 552g }{10}

A = \frac{5500}{10}

A = 550g

The average value of the second set of measurements obtained with the properly zeroed balance is 550g.

7 0
2 years ago
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