Zachary is buying 4 tires for his car. The table shows the prices and the advertised sales for the same type of tire at 4 tire s
tores.
Based on the advertised sales, at which store will Zachary get the lowest price on 4 tires?
Based on the advertised sales, at which store will Zachary get the lowest price on 4 tires?
1 answer:
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Answer:
When x = 15, y= 2
When y= 10, x= 3
Step-by-step explanation:
This is a question in inverse proportion. In this proportion, an increase in one quantity would lead to a decrease in the other and vice versa.
We are to complete the table using the relationship between x and y.
Given:
y is inversely proportional to x = y ∝ 1/x
∝ = proportional to
y ∝ 1/x
y = k × 1/x
Where k = constant of proportionality
To understand the relationship between y and x, we need to find the value of k.
y = k × 1/x
From the table,
When x = 6, y = 5
5 = k × 1/6
5 = k/6
k = 6×5 = 30
y = 30 × 1/x
y = 30/x
The above relationship would enable us find the missing parts.
When x = 15, y= ?
y = 30/15
y = 2
When y= 10, x= ?
10 = 30/x
10x = 30
x = 30/10
x= 3
Answer:
(a) The 90% confidence interval is: (0.60, 0.63) Correct interpretation is (3).
(b) The 95% confidence interval is: (0.42, 0.46) Correct interpretation is (1).
(c) First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).
Step-by-step explanation:
(a)
Let <em>X</em> = number of dog owners who take more pictures of their dog than of their significant others or friends.
Given:
<em>X</em> = 610
<em>n</em> = 1000
Confidence level = 90%
The (1 - <em>α</em>)% confidence interval for population proportion is:
The sample proportion is:
The critical value of <em>z</em> for a 90% confidence level is:
Construct a 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends as follows:
Thus, the 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends is (0.60, 0.63).
<u>Interpretation</u>:
There is a 90% chance that the true proportion of dog owners who take more pictures of their dog than of their significant others or friends falls within the interval (0.60, 0.63).
Correct option is (3).
(b)
Let <em>X</em> = number of dog owners who are more likely to complain to their dog than to a friend.
Given:
<em>X</em> = 440
<em>n</em> = 1000
Confidence level = 95%
The (1 - <em>α</em>)% confidence interval for population proportion is:
The sample proportion is:
The critical value of <em>z</em> for a 95% confidence level is:
Construct a 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend as follows:
Thus, the 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend is (0.42, 0.46).
<u>Interpretation</u>:
There is a 95% chance that the true proportion of dog owners who are more likely to complain to their dog than to a friend falls within the interval (0.42, 0.46).
Correct option is (1).
(c)
The confidence interval in part (b) is wider than the confidence interval in part (a).
The width of the interval is affected by:
- The confidence level
- Sample size
- Standard deviation.
The confidence level in part (b) is more than that in part (a).
Because of this the critical value of <em>z</em> in part (b) is more than that in part (a).
Also the margin of error in part (b) is 0.016 which is more than the margin of error in part (a), 0.015.
First, the confidence level in part(b) is <u>more than</u> the confidence level in part(a) is, so the critical value of part(b) is <u>more than</u> the critical value of part(a), Second the <u>margin of error</u> in part(b) is <u>more than</u> than in part(a).