Answer:
<u>option 1</u>
Step-by-step explanation:
The question is as shown in the attached figure.
From the figure, we can deduce that:
∠U ≅ ∠X and ∠W ≅ ∠Z and ∠V ≅ ∠Y
So, ΔUWV similar to ΔXZY
But it is required to know " How can the triangles be proven similar by the SSS similarity theorem? "
So, we need to prove the corresponding angles are proportion
With the help of the previous corresponding angles.
So, we need to show that the ratios 
are equivalent.
So, the answer is <u>option 1</u>
Original equation is 
So, 
and
If we compare this equation with the given options, we can easily find that this matches with the last one 
with P = p/2.
Hence, correct option is .
Answer:
Only Elijah's model is correct
Step-by-step explanation:
The data given in the question tells us they have 12 games left on their soccer team. Each one of them tried to simulate the fact by creating some model which look like a balance between quantities.
Elijah placed 3 cubes of value 1 and a cube of value x on one side of a balance. On the other side, he placed 15 cubes of value 1. He was obviously modeling the fact that 15 cubes (games due to play in our case) should be equal to 3 cubes (games already played) plus the x numbers left to play
This model if perfect, since the only way to equilibrate the balance is setting x to 12, the games left to play
Jonathan used a table with 3 x's in a row and a 15 in the second row, trying to model the same situation. To our interpretation, this table doesn't show the number of games left to play. If we equate 3x = 15, we get x=5 which has nothing to do with the situation explained in the question, so this model is not correct.
890×(1+0.187÷12)^(12)−890×(1+0.125÷12)^(12)=63.61....answer
Complex solutions, namely roots with a √(-1) or "i" in it, never come all by their lonesome, because an EVEN root like the square root, can have two roots that will yield the same radicand.
a good example for that will be √(4), well, (2)(2) is 4, so 2 is a root, but (-2)(-2) is also 4, therefore -2 is also a root, so you'd always get a pair of valid roots from an even root, like 2 or 4 or 6 and so on.
therefore, complex solutions or roots are never by their lonesome, their sister the conjugate is always with them, so if there's a root a + bi, her sister a - bi is also coming along too.
if complex solutions come in pairs, well, clearly a cubic equation can't yield 3 only.
