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ser-zykov [4K]
2 years ago
13

Calculate 12 x 15 by changing the numbers into friendlier numbers as we saw in the videos. Show how you work it out – write out

your methods using the number keys on your computer here: Please write your response.
Mathematics
1 answer:
kondor19780726 [428]2 years ago
7 0

Answer:

The product 12 × 15 in friendlier numbers is (10 + 2) × (10 + 5) = 180

Step-by-step explanation:

The parameter given are;

To 12 × 15 by changing the numbers into friendlier numbers

The product in 12 × 15 written with friendlier numbers (or in a simplified format can be given as follows;

12 × 15 = (10 + 2) × (10 + 5)

Which gives;

(10 + 2) × (10 + 5) = 10² + 10 × 5 + 2 × 10 + 2 × 5

From which we have;

10² + 10 × 5 + 2 × 10 + 2 × 5 = 100 + 50 + 20 + 10 = 180

Therefore;

12 × 15 = 180.

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From the graph, we see that when the production cost of wheat is $4, the equilibrium quantity is 600 units.

When the production cost lowers from $4 to $3, the supply of wheat increases, such that the equilibrium quantity increases from 600 units to 800 units.

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Forty percent of the sheets of construction paper are secondary colors. There are 25 sheets of construction paper. How many of t
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On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number
Alina [70]
<h3><u><em>Question:</em></u></h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3><em><u>Answer:</u></em></h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3><em><u>Solution:</u></em></h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

<u><em>Given items were sold for $356</em></u>

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

c \times 8 + p \times 10 = 356

8c + 10p = 356  ----- eqn 2

<u><em>Let us solve eqn 1 and eqn 2</em></u>

From eqn 1,

p = 40 - c    ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

<em>Substitute c = 22 in eqn 3</em>

p = 40 - c

p = 40 - 22

p = 18

Thus 18 pies and 22 cakes were sold

3 0
2 years ago
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