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ser-zykov [4K]
2 years ago
13

Calculate 12 x 15 by changing the numbers into friendlier numbers as we saw in the videos. Show how you work it out – write out

your methods using the number keys on your computer here: Please write your response.
Mathematics
1 answer:
kondor19780726 [428]2 years ago
7 0

Answer:

The product 12 × 15 in friendlier numbers is (10 + 2) × (10 + 5) = 180

Step-by-step explanation:

The parameter given are;

To 12 × 15 by changing the numbers into friendlier numbers

The product in 12 × 15 written with friendlier numbers (or in a simplified format can be given as follows;

12 × 15 = (10 + 2) × (10 + 5)

Which gives;

(10 + 2) × (10 + 5) = 10² + 10 × 5 + 2 × 10 + 2 × 5

From which we have;

10² + 10 × 5 + 2 × 10 + 2 × 5 = 100 + 50 + 20 + 10 = 180

Therefore;

12 × 15 = 180.

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For circle O, and m∠ABC = 55°. In the figure, ∠_____ and ∠____ have measures equal to 35°.
luda_lava [24]

Answer:

In the figure ∠ABO and ∠BCO have measures equal to 35°.

Step-by-step explanation:

<u><em>The complete question is</em></u>

For circle O, m CD=125° and m∠ABC = 55°

In the figure<____, (AOB, ABO, BOA)  and <_____ (BCO, OBC,BOC) have measures equal to 35°

The picture in the attached figure

step 1

Find the measure of angle COB

we know that

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arc\ CD=125^o

therefore

m\angle COB=125^o

step 2

we know that

AB is a tangent to the circle O at point A

so

ABC and ABO are right triangles

In the right triangle ABC

Find the measure of angle BCA

Remember that

m\angle BCA+m\angle\ ABC=90^o ---> by complementary angles in a right triangle

we have

m\angle ABC=55^o

substitute

m\angle BCA+55^o=90^o

m\angle BCA=90^o-55^o=35^o\\

step 3

In the triangle BCO

Find the measure of angle CBO

we know that

m\angle CBO+m\angle COB+m\angle BCO=180^o ---> the sum of the interior angles in any triangle must be equal to 180 degrees

we have

m\angle COB=125^o

m\angle BCO=m\angle BCA=35^o -----> have measure equal to 35 degrees

substitute

m\angle CBO+125^o+35^o=180^o

m\angle CBO=180^o-160^o=20^o

step 4

Find the measure of angle ABO

In the right triangle ABO

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we have

m\angle ABC=55^o

m\angle CBO=20^o

substitute

55^o=20^o+m\angle ABO

m\angle ABO=55^o-20^o=35^o ----> have measure equal to 35 degrees

therefore

In the figure ∠ABO and ∠BCO have measures equal to 35°.

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