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Liono4ka [1.6K]
2 years ago
5

A team of dermatological researchers were studying skin cancer among 60-70 year old American men. Suppose you were a part of the

research team and take a sample of n =70 men from this age group and calculate the mean number of skin cancer spots in the sample. Also suppose that it is known that the distribution of the number of cancer spots is right-skewed.1. How is the standard deviation of the distribution of sample means related to the population standard deviation of the number of cancer spots?a. The standard deviation of the distribution of sample means is less than the population standard deviation of the number of cancer spots.b. The standard deviation of the distribution of sample means is equal to the population standard deviation of the number of cancer spots.c. The standard deviation of the distribution of sample means is greater than the population standard deviation of the number of cancer spots.
d. We cannot be sure of any of the above answers until we examine the data.
Mathematics
1 answer:
Lostsunrise [7]2 years ago
3 0

Answer:

The correct answer is Option A.) The standard deviation of the distribution of sample means is less than the population standard deviation of the number of cancer spots.

Step-by-step explanation:

The standard deviation of the distribution of sample means is less than the population standard deviation of the number of cancer spots.

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Part A: During what interval(s) of the domain is the water balloon's height increasing?
Advocard [28]

Answer:

The answer is below

Step-by-step explanation:

The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds: A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet. Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points) Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points) Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points) Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds.

Answer:

Part A: During what interval(s) of the domain is the water balloon's height increasing?

Between 0 and 2 seconds, the height of the balloon increases from 60 feet to 75 feet

Part B: During what interval(s) of the domain is the water balloon's height staying the same?

Between 2 and 4 seconds, the height remains the same at 75 feet. Also from 10 seconds the height of the balloon is at 0 feet

Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest?

Between 4 and 6 seconds, the height of the balloon decreases from 75 feet to 40 feet (i.e. -17.5 ft/s)

Between 6 and 8 seconds, the height of the balloon decreases from 40 feet to 20 feet (i.e. -10 ft/s)

Between 8 and 10 seconds, the height of the balloon decreases from 20 feet to 0 feet (i.e. -10 ft/s)

Hence it decreases fastest from 4 to 6 seconds

Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds

From 10 seconds, the balloon is at the ground, so it remains at the ground (0 feet) even at 16 seconds

6 0
2 years ago
Which of the following best explains how this relationship and the value of sin theta can be used to find the other trigonometri
Lena [83]

Answer:

OPtion I is right

Step-by-step explanation:

Once we know sin of an angle, and it lies in II quadrant, we know that

cos, sec, tan and cot would be negative but csc will be positive.

So use the fact that

sin^{2}t+cos^{2} t=1\\cost =-\sqrt{1-sin^2 t}

Thus cos is obtained using negative square root.

Now tan = sin/cos, and sec = 1/cos:

cot =1/tan and csc =1/sin

Thus all value can be obtained easily

So option I

8 0
2 years ago
S = √3*73.5 /4.5=7 (Khufu’s pyramid)
Hatshy [7]
√3*<span>9/10 </span>/4.5=0.734 i hope this  helps you
4 0
2 years ago
Tanmay had some chocolates with him. He gave one-third of them to Akash and one-fifth of them to Sharad. Tanmay could do so with
Stels [109]

Answer:

The possible value of X are;

15, 30, 45, 60 etc

Step-by-step explanation:

The parameters given are

Number of chocolates Tanmay had = X

Number of chocolates Tanmay gave to Akash = 1/3 × X

Number of chocolates Tanmay gave to Sharad = 1/5 × X

Whereby 3 and 5 are factors of X, therefore;

3 × 5 = 15 is the lowest single factor of X

The possible values of X starting from the lowest factor are given as follows;

15 × 1 = 15

15 × 2 = 30

15 × 3 = 45

15 × 4 = 60

Hence, the possible value of X are the arithmetic progression a + (n - 1)×d

Where:

a = 15

n = 1, 2, 3, 4, ...

d = 15

Which includes;

15, 30, 45, 60

7 0
2 years ago
Sue has a crate, open at the top, in the shape of a cuboid. The internal dimensions of the crate are 36cm long by 36cm wide by 6
kondaur [170]

Answer:

Step-by-step explanation:

When the stick is placed along the diagonal  of the cuboid , shortest possible length will extend out above top of the crate .

Length of the diagonal

= \sqrt{36^2+36^2+60^2}

= 78.69 cm

the length of the stick that extends out of the crate

= 90 - 78.69

= 11.31 cm

If θ be the angle made by stick with the base

cosθ = hypotenuse of base / diagonal of cuboid

=\frac{\sqrt{2}\times36 }{78.69}

= \frac{50.90 }{78.69}

θ = 50°

7 0
3 years ago
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