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Andre45 [30]
2 years ago
13

A power line stretches down a 400-foot country road. A pole is to be put at each end of the road, and 1 in the midpoint of the w

ire. How far apart is the center pole from the left-most pole?

Mathematics
1 answer:
Usimov [2.4K]2 years ago
4 0

Answer:

The distance between the center pole and the left most pole = <em>200 ft</em>

<em></em>

Step-by-step explanation:

Given that a power line has a length of 400 ft.

Three poles are to be put, two on each end and one at the midpoint of the wire.

Let us represent this using the number line as shown in the attached diagram.

To find:

The distance between the center pole and the left most pole ?

Solution:

Please refer to the attached diagram for the number line representation of the given situation.

Point A refers to the starting of the road.

Point B refers to the mid point of the road and

Point C refers to the other end point of the road.

So, point A is a at 0.

Point C is at 400.

The mid point will be at:

AB = \dfrac{A's\ position+C's\ position}{2}\\\Rightarrow AB = \dfrac{0+400}{2}\\\Rightarrow AB = 200\ ft

The distance between the center pole and the left most pole = <em>200 ft</em>

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From the  question we are told that

     The population mean is  \mu =  28.29

      The standard deviation is \sigma  =  33.493

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        P(\= X < 33) =  [z <  \frac{33 -  \mu }{\sigma_{\= x}} ]

substituting values

       P(\= X < 33) =  [z <  \frac{33 -  28.29 }{4.48} ]

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For the second question

    Apply central limit theorem[CLT] we have  that

    P(\= X > 30 ) =  [z >  \frac{30 -  \mu }{\sigma_{\= x}} ]

substituting values

   P(\= X < 33) =  [z >  \frac{30 -  28.29 }{4.48} ]

From the z-table  we have that  

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Thus  

     P(\= X > 30) = 1- P(\= X < 30) = 1- 0.6480

     P(\= X > 30) = 0.3520

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