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Andre45 [30]
2 years ago
13

A power line stretches down a 400-foot country road. A pole is to be put at each end of the road, and 1 in the midpoint of the w

ire. How far apart is the center pole from the left-most pole?

Mathematics
1 answer:
Usimov [2.4K]2 years ago
4 0

Answer:

The distance between the center pole and the left most pole = <em>200 ft</em>

<em></em>

Step-by-step explanation:

Given that a power line has a length of 400 ft.

Three poles are to be put, two on each end and one at the midpoint of the wire.

Let us represent this using the number line as shown in the attached diagram.

To find:

The distance between the center pole and the left most pole ?

Solution:

Please refer to the attached diagram for the number line representation of the given situation.

Point A refers to the starting of the road.

Point B refers to the mid point of the road and

Point C refers to the other end point of the road.

So, point A is a at 0.

Point C is at 400.

The mid point will be at:

AB = \dfrac{A's\ position+C's\ position}{2}\\\Rightarrow AB = \dfrac{0+400}{2}\\\Rightarrow AB = 200\ ft

The distance between the center pole and the left most pole = <em>200 ft</em>

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GRAHAM CORPORATION
astra-53 [7]

Answer:

<h2>Net proceed= s-0.98nd-11</h2>

Step-by-step explanation:

Given that the shares cost $d

n shares will be =$dn

paid 2% commission to her broker= (2/100)*nd= 0.02nd

sold the share for $s

paid a fee of $11

Her net proceeds algebraically will be

Net proceed= s-nd-11-0.02nd

collect like terms

Net proceed= s-(nd-0.02nd)-11

Net proceed= s-0.98nd-11

5 0
1 year ago
The quality control manager at a light bulb factory needs to estimate the mean life of a batch (population) of light bulbs. We a
Nadusha1986 [10]

Answer:

<em>a)95%  confidence intervals for the population mean of light bulbs in this batch</em>

(325.5 ,374.5)

b)

<em>The calculated value Z = 4 > 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The manufacturer has not right to take the average life of the light bulbs is 400 hours.</em>

Step-by-step explanation:

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

The tabulated value Z₀.₉₅ = 1.96

<em>95%  confidence intervals for the population mean of light bulbs in this batch</em>

<em></em>(x^{-} - Z_{\frac{\alpha }{2} } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\frac{\alpha }{2} }\frac{S.D}{\sqrt{n} } )<em></em>

<em></em>(350 - 1.96\frac{100}{\sqrt{64} } , 350 + 1.96\frac{100}{\sqrt{64} } )<em></em>

(350 -24.5, 350 +24.5)

(325.5 ,374.5)

b)

<u><em>Explanation</em></u>:-

Given mean of the Population μ = 400

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

<u><em>Null hypothesis</em></u> : H₀:The manufacturer has right to take the average life of the light bulbs is 400 hours.

μ = 400

<u><em>Alternative Hypothesis: H₁:</em></u> μ ≠400

<u><em>The test statistic </em></u>

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

Z = \frac{350 -400}{\frac{100}{\sqrt{64} } }

|Z| = |-4|

The tabulated value   Z₀.₉₅ = 1.96

The calculated value Z = 4 > 1.96 at 0.05 level of significance

Null hypothesis is rejected.

<u><em>Conclusion:</em></u>-

The manufacturer has not right to take the average life of the light bulbs is 400 hours.

5 0
2 years ago
On babylonian tablet ybc 4652, a problem is given that translates to this equation: x (x/7) (1/11) (x (x/7)) = 60 what is the so
Yanka [14]
Thanks for posting your question here. The answer to the above problem is x = <span>48.125. Below is the solution:
</span>
 x+x/7+1/11(x+x/7)=60 
x = x/1 = x • 7/7
x <span>• 7 + x/ 7 = 8x/7 - 60 = 0
</span>x + x/7 + 1/11 <span>• 8x/7 - 60 = 0
</span>8x <span>• 11 + 8x/ 77 = 96x/ 77
</span>96x - 4620 = 12 <span>• (8x-385)
</span>8x - 385 = 0
x = 48.125


5 0
2 years ago
Read 2 more answers
After calculating the sample size needed to estimate a population proportion to within 0.05, you have been told that the maximum
Svetlanka [38]

Answer:  40000

Step-by-step explanation:

The formula to find the sample size is given by :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2, where p is the prior estimate of the population proportion.

Here we can see that the sample size is inversely proportion withe square of margin of error.

i.e. n\ \alpha\ \dfrac{1}{E^2}

By the equation inverse variation, we have

n_1E_1^2=n_2E_2^2

Given : E_1=0.05   n_1=1000

E_2=0.025

Then, we have

(1000)(0.05)^2=n_2(0.025)^2\\\\\Rightarrow\ 2.5=0.000625n_2\\\\\Rightarrow\ n_2=\dfrac{2.5}{0.000625}=4000

Hence, the sample size will now have to be 4000.

6 0
1 year ago
During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th
ser-zykov [4K]

Answer: 0.5898

Step-by-step explanation:

Given :  J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901  (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

P(X=x)^nC_xp^x(1-p)^{n-x}

, where n= total trials

p= probability of getting in each trial.

Let x be binomial variable that represents the number of a=makes.

n= 14

p= 0.901     (from (1))

The probability that he makes at least 13 of them will be :-

P(x\geq13)=P(x=13)+P(x=14)

=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898

∴ The required probability = 0.5898

5 0
2 years ago
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