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Snezhnost [94]
2 years ago
6

points Q and R are midpoints of the sides of triangle ABC. Triangle A B C is cut by line segment Q R. Point Q is the midpoint of

side A B and point R is the midpoint of side A C. The lengths of A Q and Q B are 4 p, the length of Q R is 2 p + 3, and the length of C B is 6 p minus 4. The lengths of A R and R C are congruent. What is AQ? 10 units 14 units 20 units 32 units

Mathematics
2 answers:
notsponge [240]2 years ago
8 0

Answer:

AQ = 20 units

Step-by-step explanation:

I tried figuring in the pic below..

Similar triangles are triangles whose corresponding measures are proportional. All of their corresponding angles are also congruent. There are theorems and postulates that prove triangle similarity. Usually they requrie at least three parts of each triangle. The symbol for similarity is ~.

We have two triangles in the figure. ΔAQR and ΔABC. We will prove first that they are similar.

marta [7]2 years ago
6 0

Answer:

20

Step-by-step explanation:

RQ is 1/2 of CB, so 2(2p+3)=6p-4. This would make p=5. Then, 5*4=20.

(also it is right on edgenuity)

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Please help me with this question
natulia [17]

what's up

Seek understand, to be understood!

To get the answer we need the formula or source.

The question in another way if 4cm=1.2km, what is the 10cm=--------

first, you have to use the crisscross.

4cm=1.2km

10cm= x it is variable  

then, 4xx= 1.2kmx10cm

4x=12km

4x/4= 12/4

x=3km  


4 0
2 years ago
The Green family is a family of six people. They have used 4,885.78 gallons of water so far this month. They cannot exceed 9,750
prohojiy [21]

Answer:

The inequality is  6x+4,885.78\leq 9,750.05

x\leq 810.71\ gal

Step-by-step explanation:

Let

x -----> amount of water that can be used by only one family member for the rest of the month

we know that

6x+4,885.78\leq 9,750.05

Solve for x

Subtract 4,885.78 both sides

6x\leq 9,750.05-4,885.78

6x\leq 4,864.27

Divide by 6 both sides

x\leq 4,864.27/6

x\leq 810.71\ gal

3 0
2 years ago
Read 2 more answers
What is 0.666667 as a fraction ?
Olenka [21]
0.666667 as a fraction is 2/3
7 0
2 years ago
Read 2 more answers
If JL=18, NK=12, and ML=10, find the perimeter of JKLM<br> A. 42<br> B. 45<br> C. 50<br> D. 56
snow_lady [41]

Answer:

The perimeter of the kite JKLM is 50 units ⇒ C

Step-by-step explanation:

The longest diagonal of the kite is its axis of symmetry which means the longest diagonal divides the kite into two congruent triangles

∵ JKLM is a kite

∵ KM is the longest diagonal

∴ KM is divides the kite into two congruent triangles

∴ Δ JKM is congruent to Δ LKM

∴ JK = LK

∴ JM = ML

∵ ML = 10 units

∴ JM = 10 units

∵ The diagonals of the kite are perpendicular

∴ KM ⊥ JL

∵ KM and JL intersected at N

∴ m∠JNK = 90°

∵ KM is the axis of symmetry of kite JKLM

∴ KM bisects JL at N

∴ JN = NL = \frac{1}{2} JL

∵ JL = 18 units

∴ JN = \frac{1}{2} (18)

∴ JN = 9 units

In Δ JNK

∵ m∠JNK = 90°

∵ JN = 9 units

∵ NK = 12 units

- By using Pythagoras Theorem

∵ (JK)² = (JN)² + (NK)²

∴ (JK)² = (9)² + (12)²

∴ (JK)² = 81 + 144

∴ (JK)² = 225

- Take √ for both sides

∴ JK = 15 units

∵ Jk = LK

∴ Lk = 15 units

∵ The perimeter of the kite is the sum of its 4 sides

∴ P = JK + KL + LM + MJ

∵ JK = LK = 15

∵ JM = ML = 10

∴ P = 15 + 15 + 10 + 10

∴ P = 50

The perimeter of the kite JKLM is 50 units

7 0
2 years ago
XY=4n+3,YZ=2n-7,XZ=22
Agata [3.3K]
Choose one of the equations, then try and rewrite in terms of 1 Unknown, eg I've chosen XZ= 22 and am going to write it in terms of X

XZ = 22
Z = 22/X (this is writing Z in terms of X)
So... X(22/X)= 22
22/X=22X
22 = 22X^2 (* ^2 is to the power 2)
Therefore X = 1
And Z= 22

Use this to solve the remaining equations

1xY = 4n + 3
22Y= 2n - 7
Then rearrange and do simultaneous equations

22Y - 66 = 88n
22Y + 7 = 2n
-73 = 86n
n = -73/86

It is very very likely that I have made a mistake somewhere here given the strange number I have for n but I spent far too long on this not to post it ahaha, even if the numbers are incorrect this is the general method I would follow
7 0
2 years ago
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