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Snezhnost [94]
1 year ago
6

points Q and R are midpoints of the sides of triangle ABC. Triangle A B C is cut by line segment Q R. Point Q is the midpoint of

side A B and point R is the midpoint of side A C. The lengths of A Q and Q B are 4 p, the length of Q R is 2 p + 3, and the length of C B is 6 p minus 4. The lengths of A R and R C are congruent. What is AQ? 10 units 14 units 20 units 32 units

Mathematics
2 answers:
notsponge [240]1 year ago
8 0

Answer:

AQ = 20 units

Step-by-step explanation:

I tried figuring in the pic below..

Similar triangles are triangles whose corresponding measures are proportional. All of their corresponding angles are also congruent. There are theorems and postulates that prove triangle similarity. Usually they requrie at least three parts of each triangle. The symbol for similarity is ~.

We have two triangles in the figure. ΔAQR and ΔABC. We will prove first that they are similar.

marta [7]1 year ago
6 0

Answer:

20

Step-by-step explanation:

RQ is 1/2 of CB, so 2(2p+3)=6p-4. This would make p=5. Then, 5*4=20.

(also it is right on edgenuity)

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A poll conducted a week before the school election to the student council showed that Janice would win with 63% of the vote. The
k0ka [10]

OPTIONS:

No, because she could receive as low as 14% of the vote.

No, because she could receive as low as 49% of the vote.

Yes, because she could receive as much as 77% of the vote.

Yes, because the poll stated that she will win with 63% of the vote.

Answer:

No, because she could receive as low as 49% of the vote.

Step-by-step explanation:

Given that:

Poll suggestion = 63%

Margin of Error (E) = 14%

This means that; the range or interval in which the vote obtained could fall would be ;

Poll suggestion ± margin of Error

63% ± 14%

Lower bound attainable = (63% - 14%) = 49%

Upper bound attainable = (63% + 14%) = 77%

Since, winning actually requires obtaining atleast half of the votes (that is 50%) ; and suggested poll suggested votes could fall as low as 49% ; then Janice can't be so confident of victory.

8 0
1 year ago
Sue’s Corner Market has a markup of 60% on bottled water. If the market sells a bottle of water for $2, find the original amount
lakkis [162]

Markup is the amount added to the cost price of goods to cover overhead and profit.

Sue’s Corner Market has a markup of 60% on bottled water.

Let us say original price was $x.

Now price after markup is $2.

So we can make an equation like:

original price + markup price = price after markup

x + 60% of x =2

x + 0.6x =2

1.6x =2

dividing both sides by 1.6

x= 1.25

So original price was 1.25 dollars.

5 0
1 year ago
Read 2 more answers
Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. From the shipment you take
MrRissso [65]

Answer:

mean (μ) = 4.25

Step-by-step explanation:

Let p = probability of a defective computer components = \frac{68}{400} = 0.17

let q = probability of a non-defective computer components = \frac{332}{400} = 0.83

Given random sample n = 25

we will find mean value in binomial distribution

The mean of binomial distribution = np

here 'n' is sample size and 'p' is defective components

mean (μ) = 25 X 0.17 = 4.25

<u>Conclusion</u>:-

mean (μ) =  4.25

6 0
2 years ago
The relationship between money earned and hours worked is linear. Joe computes the slope between (4, 30) and (12, 90), then comp
____ [38]
Finding the slope of both coordinates, you'll get 15/2. The slopes are the same 
3 0
2 years ago
Read 2 more answers
(b) A department store has 7,000 charge accounts. The comptroller takes a random sample of 36 of
galben [10]

Answer:

a.0.8664

b. 0.23753

c. 0.15866

Step-by-step explanation:

The comptroller takes a random sample of 36 of the account balances and calculates the standard deviation to be N42.00. If the actual mean (1) of the account balances is N175.00, what is the probability that the sample mean would be between

a. N164.50 and N185.50?

b. greater than N180.00?

c. less than N168.00?

We solve the above question using z score formula

z = (x-μ)/σ/√n where

x is the raw score,

μ is the population mean = N175

σ is the population standard deviation = N42

n is random number of sample = 36

a. Between N164.50 and N185.50?

For x = N 164.50

z = 164.50 - 175/42 /√36

z = -1.5

Probability value from Z-Table:

P(x = 164.50) = 0.066807

For x = N185.50

z = 185.50 - 175/42 /√36

z =1.5

Probability value from Z-Table:

P(x=185.50) = 0.93319

Hence:

P(x = 185.50) - P(x =164.50)

= 0.93319 - 0.066807

= 0.866383

Approximately = 0.8664

b. greater than N180.00?

x > N 180

Hence:

z = 180 - 175/42 /√36

z = 5/42/6

z = 5/7

= 0.71429

Probability value from Z-Table:

P(x<180) = 0.76247

P(x>180) = 1 - P(x<180) = 0.23753

c. less than N168.00?

x < N168.

z = 168 - 175/42 /√36

z = -7/42/6

z = -7/7

z = -1

Probability value from Z-Table:

P(x<168) = 0.15866

4 0
1 year ago
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