The number of pages in the book is 180
<u>Explanation:</u>
The first thing we should do is to convert these fractions to percentage
3/4 of the remainder on thursday:
Thursday: (100 - (13.33 + 33.33 + 22.22) * (3/4) = 23.33%
he still has 14 pages left to read on friday
Friday: [100 - (13.33 + 33.33 + 22.22) ] - 23.33 = 7.77%
Which means that 14 pages represent 7.77% of the book.
Therefore the number of pages of the book is given by:
Therefore, number of pages in the book is 180
Jana was prescribed medication. m = 250(0.75)^h
6 hours after Jana took her medication, Allison was prescribed the same.
m=250(0.75)^(h-6)
<span>At any time after she has taken the medication, Allison has how many times more milligrams of medication in her body?
</span>
Same with Jana, Allison's medication content in her body will decrease by 25% after each hour.
Let h = 6
Jana: m = 250(0.75)^6 = 250(0.178) = 44.50
Allison: m = 250(0.75)^6-6 = 250(1) = 250
250 - 44.50 = 205.50
On hour 6, Allison will have 205.5 mg more of the medicine than Jana.
Hello,
Here is the first answer:
The answer is "16.6 or 17%".
Reason:
<span>636</span><span> x 100% = 16.6666666667%
Here is your second answer:
The answer is "50%".
Reason:
</span><span>36</span> x 100% = 50%
<span>
Here is your third answer:
The answer is "43.3 or 43%".
Reason:
</span><span>52120</span> x 100% = 43.3333333333%
Here is your fourth answer:
The answer is "328.5 or 329%".
Reason:
<span>11535</span><span> x 100% = 328.5714285714%
If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit</span>
9514 1404 393
Answer:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
142 fish
Step-by-step explanation:
A) The differential equation is modified by adding a -50 fish per year constant term:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
__
B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.
(0.4/1200)(N)(1200-N) -50 = 0
N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient
N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square
(N -600)^2 = 210,000 . . . . . simplify
N = 600 + √210,000 ≈ 1058
This steady-state number of fish is ...
1200 - 1058 = 142 . . . . below the original carrying capacity
