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Sladkaya [172]
1 year ago
5

Can someone please check my answer for this question?

Mathematics
2 answers:
PtichkaEL [24]1 year ago
6 0

Answer:

Total expense is $275.20.

Monthly average is $45.87.

Step-by-step explanation:

January       February     March     April     May     June

$48.28       $48.58       $41.35     $48.28  $43.45  $45.26

Total expense = 48.28+48.58+41.35+48.28+43.45+45.26 = $275.20

Monthly average = \frac{275.20}{6} = $45.87

faust18 [17]1 year ago
5 0

Answer: its correct the everage os 45.8666 but can be rounded to 45.87

Step-by-step explanation:

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Kelvin and Lewie each design surveys in order to determine the average number of people who buy food at the mall. Kelvin surveys
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Answer:

Lewie Survey produces less valid result.

Step-by-step explanation:

Given:

1. Kelvin surveys every other person leaving the food area.

2. Lewie surveys every fifth person leaving the mall's main entrance.

Therefore,

Kelvin will able to produce valid result as he is surveying every person who is leaving food court.

Means,

There are high chances that would have bought food from the court.

Whereas,

Lewie is surveying every fifth person leaving the the mall's entrance.

Therefore,

Here probability to produce valid result is less as they may have not buy food or they may visited other shops.

So, Lewie survey will produce less valid result.

8 0
1 year ago
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The quality control manager at a light bulb factory needs to estimate the mean life of a batch (population) of light bulbs. We a
Nadusha1986 [10]

Answer:

<em>a)95%  confidence intervals for the population mean of light bulbs in this batch</em>

(325.5 ,374.5)

b)

<em>The calculated value Z = 4 > 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The manufacturer has not right to take the average life of the light bulbs is 400 hours.</em>

Step-by-step explanation:

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

The tabulated value Z₀.₉₅ = 1.96

<em>95%  confidence intervals for the population mean of light bulbs in this batch</em>

<em></em>(x^{-} - Z_{\frac{\alpha }{2} } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\frac{\alpha }{2} }\frac{S.D}{\sqrt{n} } )<em></em>

<em></em>(350 - 1.96\frac{100}{\sqrt{64} } , 350 + 1.96\frac{100}{\sqrt{64} } )<em></em>

(350 -24.5, 350 +24.5)

(325.5 ,374.5)

b)

<u><em>Explanation</em></u>:-

Given mean of the Population μ = 400

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

<u><em>Null hypothesis</em></u> : H₀:The manufacturer has right to take the average life of the light bulbs is 400 hours.

μ = 400

<u><em>Alternative Hypothesis: H₁:</em></u> μ ≠400

<u><em>The test statistic </em></u>

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

Z = \frac{350 -400}{\frac{100}{\sqrt{64} } }

|Z| = |-4|

The tabulated value   Z₀.₉₅ = 1.96

The calculated value Z = 4 > 1.96 at 0.05 level of significance

Null hypothesis is rejected.

<u><em>Conclusion:</em></u>-

The manufacturer has not right to take the average life of the light bulbs is 400 hours.

5 0
2 years ago
Round 22360 to 1 significant figure
monitta
This link to a video will help

https://youtu.be/k3RwfEvqrB8
7 0
1 year ago
Read 2 more answers
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