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Sladkaya [172]
2 years ago
5

Can someone please check my answer for this question?

Mathematics
2 answers:
PtichkaEL [24]2 years ago
6 0

Answer:

Total expense is $275.20.

Monthly average is $45.87.

Step-by-step explanation:

January       February     March     April     May     June

$48.28       $48.58       $41.35     $48.28  $43.45  $45.26

Total expense = 48.28+48.58+41.35+48.28+43.45+45.26 = $275.20

Monthly average = \frac{275.20}{6} = $45.87

faust18 [17]2 years ago
5 0

Answer: its correct the everage os 45.8666 but can be rounded to 45.87

Step-by-step explanation:

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This is a very long question. I'm not going to write all of it out but I will give you a starting point. Find your x by making y in the formula equal to 0.

2x + 3y = 1470

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2x = 1470

x = 735

Your furthest point on the x axis is (735,0).

Do the same for y.

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2 years ago
The ratio of length to width in a rectangle is 3 to 1. If the perimeter of the rectangle is 128 feet, what is the length of the
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Step-by-step explanation:

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2 years ago
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Let X represent the amount of time until the next student will arrive in the library parking lot at the university. If we know t
Ber [7]

Answer:

The probability that it will take more than 10 minutes for the next student to arrive at the library parking lot is 0.0821.

Step-by-step explanation:

The random variable <em>X</em> is defined as the amount of time until the next student will arrive in the library parking lot at the university.

The random variable <em>X</em> follows an Exponential distribution with mean, <em>μ</em> = 4 minutes.

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f_{X}(x)=\lambda e^{\lambda x};\ x\geq 0, \lambda >0

The parameter of the exponential distribution is:

\lambda=\frac{1}{\mu}=\frac{1}{4}=0.25

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10}{0.25e^{-0.25x}}\, dx

                 =0.25\times \int\limits^{\infty}_{10}{e^{-0.25x}}\, dx\\=0.25\times |\frac{e^{0.25x}}{-0.25}|^{\infty}_{10}\\=(e^{-0.25\times \infty})-(e^{-0.25\times 10})\\=0.0821

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3 0
2 years ago
Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?
In-s [12.5K]

Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)=2x^{3}-26x-24

2x^{3}-26x-24=0

2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\

=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\

=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis



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2 years ago
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Answer:

A

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so

=2.6334 x 10-5

7 0
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