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alukav5142 [94]

2 years ago

13

Regina takes yoga classes 2 days a week at the community center the cost for the classes is $72 and Regina pays extra$12 to rent

the yoga equipment used in class

1 answer:

Kamila [148]2 years ago

4 0

Answer:

gfh

Step-by-step explanation:

dhgdh

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An investor has $ 500000 to spend. There investments are being considered, each having an expected annual interest rate. The int

enyata [817]

That's a lot of money and words. I don't appreciate this. I would probably just break down and cry tbh

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2 years ago

A quarter is approximately 0.07 inches thick. A dollar bill is approximately 4.3 × 10-3 inches thick.

nlexa [21]

Answer:

m = 6.57 and n = -2

Step-by-step explanation:

To answer this question you will covert the thickness of a dollar to standard notation and then compare the two values.

0.07 =compared to 0.0043 = 0.0657

0.0657 = 6.57 x 10^-2

A quarter is thicker than a dollar by 6.57 x 10^-2.

m = 6.57 and n = -2

8 0

1 year ago

Pat's Pizza made 21 cheese pizzas, 14 veggie pizzas, 23 pepperoni pizzas, and 14 sausage pizzas yesterday.

MatroZZZ [7]

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7 0

2 years ago

Read 2 more answers

Two cross sections of a right hexagonal pyramid are obtained by cutting the pyramid with planes parallel to the hexagonal base.

Tanya [424]

Answer:

The larger cross section is 24 meters away from the apex.

Step-by-step explanation:

The cross section of a right hexagonal pyramid is a hexagon; therefore, let us first get some things clear about a hexagon.

The length of the side of the hexagon is equal to the radius of the circle that inscribes it.

The area is

$A=\frac{3\sqrt{3} }{2} r^2$

Where $r$ is the radius of the inscribing circle (or the length of side of the hexagon).

Now we are given the areas of the two cross sections of the right hexagonal pyramid: $A_1=216\:ft^2\: \:\:\:A_2=486\:ft^2$

From these areas we find the radius of the hexagons:

$r_1=\sqrt{\frac{2A_1}{3\sqrt{3} } } =\sqrt{\frac{2*216}{3\sqrt{3} } }=\boxed{9.12ft}$

$r_2=\sqrt{\frac{2A_2}{3\sqrt{3} } } =\sqrt{\frac{2*486}{3\sqrt{3} } }=\boxed{13.68ft}$

Now when we look at the right hexagonal pyramid from the sides ( as shown in the figure attached ), we see that $r_1$ $r_2$ form similar triangles with length $H$

Therefore we have:

$\frac{H-8}{r_1} =\frac{H}{r_2}$

We put in the numerical values of $r_1$ , $r_2$ and solve for $H$ :

$\boxed{H=\frac{8r_2}{r_2-r_1} =\frac{8*13.677}{13.68-9.12} =24\:feet.}$

8 0

2 years ago

A geometry teacher asked Charlene to define “acute triangle.” Charlene said that an acute triangle is a triangle whose three int

Slav-nsk [51]

By definition we have to:
Acute triangle - It is a triangle that has all acute angles. An acute angle is one whose degree of measurement is less than 90.
Therefore, Charlene's definition is correct.
Charlene said:
triangle is a triangle whose three interior angles have measures less than 90 °
Answer:
C.Yes, because this definition fits all acute triangles and does not fit triangles that are not acute.

4 0

2 years ago