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miskamm [114]
2 years ago
13

Find the volume of a pyramid 5 yards tall if the base is a rectangle 15 feet by 6 feet.

Mathematics
2 answers:
Contact [7]2 years ago
5 0
If i am right is V<span>=</span><span>150</span>
BaLLatris [955]2 years ago
3 0
V=lwh/3=5*15*6/3=160
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Which values of c will cause the quadratic equation –x2 + 3x + c = 0 to have no real number solutions? Check all that apply.
vitfil [10]
A quadratic equation has no real number solutions than the discriminant is less than zero 

D < 0 

(b^2 -4ac) < 0 

(9 -4(-1*c) < 0

(9+4c) < 0

4c < -9

c < -9/4

hope this will help you 
4 0
2 years ago
Read 2 more answers
I AM GIVING 99 POINTS!
faust18 [17]
In 1944 Elion joined the Burroughs Wellcome Laboratories (now part of GlaxoSmithKline (a company that makes prescription medicines)). There she was first the assistant and then the colleague of Hitchings, with whom she worked for the next four decades. Elion and Hitchings developed an array (variety) of new drugs that were effective against leukemia, autoimmune disorders, urinary-tract infections, gout, malaria, and viral herpes. Their success was due primarily to their innovative (characterized by new or unique) research methods. Rather than using the trial-and-error approach used by previous pharmacologists, Elion and Hitchings examined the difference between the biochemistry of normal human cells and that of cancer cells, bacteria, viruses, and other pathogens (disease-causing agents). They used this information to create drugs that could target a particular pathogen without harming the human host's normal cells. Their methods enabled them to eliminate much of the guesswork and wasted effort typical in previous drug research.
3 0
1 year ago
Read 2 more answers
The equation ​ yˆ=−6.2x2+51.5x+10.2 ​ approximates the average number of cars that pass through an intersection x hours after 3:
Mars2501 [29]
Notice that form 3 pm to 6:30 pm 3.5 hours have passed.
Since the function y=-6 x^{2} +51.5x+10.2 represent the average number of cars that pass through an intersection x hours after 3:00 p.m, we are going to replace x with 3.5 to find <span>the average number of cars that pass through the intersection at 6:30 p.m
</span>y=-6 x^{2} +51.5x+10.2
y=-6 (3.5)^{2} +51.5(3.5)+10.2
y=-6(12.25)+180.25+10.2
y=-73.5+190.45
y=116.95

We can conclude that the <span>average number of cars that pass through an intersection at 6:30 pm is approximately 117. </span>
8 0
1 year ago
Read 2 more answers
The diameters of bolts produced in a machine shop are normally distributed with a mean of 5.725.72 millimeters and a standard de
suter [353]

Answer:

Top 5% is 5.84 milliters and the bottom 5% is 5.60 millimeters.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 5.72, \sigma = 0.07

Top 5%:

X when Z has a pvalue of 0.95. So X when Z = 1.645

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 5.72}{0.07}

X - 5.72 = 1.645*0.07

X = 5.84

Bottom 5%:

X when Z has a pvalue of 0.05. So X when Z = -1.645

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 5.72}{0.07}

X - 5.72 = -1.645*0.07

X = 5.60

Top 5% is 5.84 milliters and the bottom 5% is 5.60 millimeters.

7 0
2 years ago
Read 2 more answers
Organisms A and B start out with the same population size. Organism A's population doubles every day. After 5 days, the populati
Zigmanuir [339]

Answer:

The number of times organism B's population is larger than organism A's population after 8 days is 32 times

Step-by-step explanation:

The population of organism A doubles every day, geometrically as follows

a, a·r, a·r²

Where;

r = 2

The population after 5 days, is therefore;

Pₐ₅ = = 32·a

The virus cuts the population in half for three days as follows;

The first of ta·2⁵ he three days = 32/2 = 16·a

The second of the three days = 16/2 = 8·a

After the third day, Pₐ = 8/2 = 8·a

The population growth of organism B is the same as the initial growth of organism A, therefore, the population, P₈ of organism B after 8 days is given as follows;

P₈ =  a·2⁸ = 256·a

Therefore, the number of times organism B's population is larger than organism A's population after 8 days is P₈/Pₐ = 256·a/8·a = 32 times

Which gives, the number of times organism B's population is larger than organism A's population after 8 days is 32 times.

3 0
2 years ago
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