<h2>
Answer:</h2>

<h2>
Step-by-step explanation:</h2>
The graphs of
can be obtained from the graph of the cosine function using the reciprocal identity, so:

But in this problem, the graph stands for the function:

Because the period is now 4π as indicated and for
in the figure and this can be proven as follows:

Also,
as indicated in the figure and this can be proven as:

Answer:
We have to get the average transaction time down to 371 seconds or 6 minutes 11 seconds.
Step-by-step explanation:
The average transaction time for this location is 6 minutes and 52 seconds.



The average transaction time for this location is

The average transaction time is reduced by 10%.
The average transaction time of this location reduced to 371 seconds.
The average transaction time of this location reduced to 6 minutes 11 seconds.
21.6 ÷ 0.4 = 54 times for green
21.6 ÷ 0.6 = 36 times for purple
Together, 90 beads. Separately, 54 green and 36 purple.
Answer:
A. {(–4, 3), (–2, 7), (–1, 0), (4, –3), (11, –7)}
Step-by-step explanation:
I just did the quiz but basically you can switch the coordinates around to view the coordinates of the inverse function. If there are x values that are the same number, it does not pass the line test making it not a function with an inverse function.
Question: What's the joint frequency a 9th grader liked math?
<h3>Answer: 3%</h3>
Explanation:
Check out the attached image below. I've filled in the table with the missing values. The upper left corner is 3 because 7+3 = 10 in the first column. You'll fill in the other values in a similar fashion. Once we filled out the table, we can answer all of these questions. There are 3 ninth graders who like math out of 100 people total. So the final answer is 3/100 = 0.03 = 3%.
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Question: What's the marginal relative frequency of 9th graders surveyed?
<h3>Answer:
10%</h3>
Explanation:
Again, refer to the table to find that there are 10 ninth graders out of 100 total. So 10/100 = 0.10 = 10% is the answer.
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Question: Given a student was in 10th grade, what's the likelihood the student preferred English?
<h3>Answer:
46%</h3>
Explanation:
We only focus on the 10th graders because of the "given". There are 23 people in this row who like English out of 50 total sophomores. So 23/50 = 0.46 = 46% of the tenth graders liked English.
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Question: Given the subject was science, what's the likelihood the student was a freshman?
<h3>Answer:
72.5%</h3>
Explanation:
Focus on the science column only. There are 29 freshmen out of 40 students total. We get the percentage of 29/40 = 0.725 = 72.5%