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2 years ago

In ∆ABC, AC = 15 centimeters, m B = 68°, and m C = 24°. What is BC to two decimal places?

2 answers:

4 0

I dont know which math you are in but you can use the law of sins. (A/sin(a))=(B/sin(b)) where the capital letters are the sides (in this case you would put AC or whatever side length it is) and the lower case letters are the measures on the angles.
that may have been confusing but look up the laws of sines and cosine because you'll need to learn them and it's very helpful.
15/sin68 = x/sin88 x is the side BC and to get angle A, do 180-68-24
so x= sin88 (15/sin68)
so the answer to this question would be 16.17 cm

Afina-wow [57]2 years ago

3 0

Answer:

16.17 cm would be the answer

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Obtain two numbers such their HCF is 20 and their LCM is 300....... By steps...<br><br>

Gemiola [76]

Answer:

60 and 100

Step-by-step explanation:

Look for 2 multiples of 20 which are also factors of 300.

No need to go all Mathematician.

It's simple, no long explanation needed

7 0

2 years ago

A bucket that has a mass of 30 kg when filled with sand needs to be lifted to the top of a 30 meter tall building. You have a ro

Rom4ik [11]

Answer:

765 J

Step-by-step explanation:

We are given;

Mass of bucket = 30 kg

Mass of rope = 0.3 kg/m

height of building= 30 meter

Now,

work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand

Or W = W1 + W2

Work done in lifting the rope is given as,

W1 = Force x displacement

W1 = (30,0)∫(0.2x .dx)

Integrating, we have;

W1 = [0.2x²/2] at boundary of 30 and 0

W1 = 0.1(30²)

W1 = 90 J

work done in lifting the sand is given as;

W2 = (30,0)∫(F .dx)

F = mx + c

Where, c = 30 - 15 = 15

m = (30 - 15)/(30 - 0)

m = 15/30 = 0.5

So,

F = 0.5x + 15

Thus,

W2 = (30,0)∫(0.5x + 15 .dx)

Integrating, we have;

W2 = (0.5x²/2) + 15x at boundary of 30 and 0

So,

W2 = (0.5 × 30²)/2) + 15(30)

W2 = 225 + 450

W2 = 675 J

Therefore,

work done lifting the bucket (sand and rope) to the top of the building,

W = 90 + 675

W = 765 J

5 0

2 years ago

If you take out a $15,000 loan for a period of 36 months at a 5.4% annual interest rate, how much of your first monthly payment

Tems11 [23]

Answer:

The amount that will go towards the balance is 385.71.

Step-by-step explanation:

The information provided is:

P = Principal of loan = $15,000

r = interest rate = 5.4% p.a. = $\frac{0.054}{12}= 0.0045$

n = number of periods = 36

The amount of the monthly payment that will go towards the balance is:

Amount towards the balance = EMI - Interest

First compute the Equated monthly installments (EMI) as follows:

$EMI=\frac{P\times r\times (1+r)^{n}}{(1+r)^{n}-1} \\=\frac{15000\times0.0045\times(1+0.0045)^{36}}{(1+0.0045)^{36}-1} \\=\frac{79.3125}{0.175}\\=453.21$

Now compute the interest as follows:

$Interest=P\times r\\=15000\times0.0045\\=67.5$

The amount that will go towards the balance is,

Amount towards the balance = EMI - Interest

= 453.21 - 67.5

= 385.71

Thus, the amount that will go towards the balance is 385.71.

4 0

2 years ago

Read 2 more answers

Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us

grigory [225]

Answer:

The confidence interval on this case is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

$\bar X = \frac{62.532+76.478}{2}= 69.505$

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

$\bar X$ represent the sample mean