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2 years ago

In ∆ABC, AC = 15 centimeters, m B = 68°, and m C = 24°. What is BC to two decimal places?

2 answers:

4 0

I dont know which math you are in but you can use the law of sins. (A/sin(a))=(B/sin(b)) where the capital letters are the sides (in this case you would put AC or whatever side length it is) and the lower case letters are the measures on the angles.
that may have been confusing but look up the laws of sines and cosine because you'll need to learn them and it's very helpful.
15/sin68 = x/sin88 x is the side BC and to get angle A, do 180-68-24
so x= sin88 (15/sin68)
so the answer to this question would be 16.17 cm

Afina-wow [57]2 years ago

3 0

Answer:

16.17 cm would be the answer

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1 year ago

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2 years ago

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Meeting at least one person with the flu in thirteen random encounters on campus when the infection rate is 2% (2 in 100 people

s344n2d4d5 [400]

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23.1% probability of meeting at least one person with the flu

Step-by-step explanation:

For each encounter, there are only two possible outcomes. Either the person has the flu, or the person does not. The probability of a person having the flu is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Infection rate of 2%

This means that $p = 0.02$

Thirteen random encounters

This means that $n = 13$

Probability of meeting at least one person with the flu

Either you meet none, or you meet at least one. The sum of the probabilities of these outcomes is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{13,0}.(0.02)^{0}.(0.98)^{13} = 0.7690$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.769 = 0.231$

23.1% probability of meeting at least one person with the flu

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2 years ago

P=100a÷t solve for a

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