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2 years ago

Divide 3p2 + 6p + 2 by 3p2.

Mathematics

2 answers:

Butoxors [25]2 years ago

6 0

Answer:

A=6p

B=1

C=2/p

Step-by-step explanation:

i hope this helps!

kondor19780726 [428]2 years ago

4 0

We need to divide

$\frac{3p^2+6p+2}{3p}$

So, we can divide each terms of the numerator by 3p. So,

$\frac{3p^2}{3p} +\frac{6p}{3p} +\frac{2}{3p}$

= $p+2+\frac{2}{3p}$

\frac{2}{3p} [/tex] cannot be further simplify. So, the final answer is:

$p+2+\frac{2}{3p}$

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Michael starts a new paper company. The function fff models the company's net worth (in thousands of dollars) as a function of t

nikitadnepr [17]

Answer:

is 0,14

Step-by-step explanation:

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4 0

2 years ago

Tyler needs to complete the table for his consumer science class. He knows that 1 tablespoon contains 3 teaspoons and that 1 cup

olga_2 [115]

Answer:

1 cup = 48 teaspoons

C = 48t

Step-by-step explanation:

Given:

1 tablespoon = 3 teaspoons

1 cup = 16 tablespoon

Write an equation that represents the number of teaspoons, t, contained in a cup, C.

Since

1 tablespoon = 3 teaspoons

And

1 cup = 16 tablespoon

Then

1 cup = 3 teaspoons × 16

1 cup = 48 teaspoons

Let

cup = C

Teaspoons = t

Therefore,

C = 48t

3 0

2 years ago

Dominic runs a farm stand that sells peaches and grapes yesterday Dominic sold 34 pounds of peaches and 45 lb of grapes for a to

iren2701 [21]

Answer:34p+16g=208

47p+16g=208

Step-by-step explanation:

Let p=the price of each pound of peaches.

Let g=the price of each pound of grapes.

Each pound of peaches sells for $p, so 34 pounds of peaches will bring in 34p dollars. Each pound of grapes will bring in 45g dollars. Therefore, the total amount 34p+45g=192.25

Likewise, if 47 pounds of peaches and 16 pounds of grapes brought in $208 then

47p+16g=208

34p+45g=192.25

47+16g=208

3 0

2 years ago

Choose the function whose graph is given by:

katen-ka-za [31]

Answer:

D. $y=\tan (x-\pi)+2$

Step-by-step explanation:

We are given the graph of the transformed tangent function.

As, we can see that the graph is shifted 2 units upwards.

That is, the parent function is translated 2 units up.

So, the new function will be of the form, $y=\tan (x)+2$ .

Thus, options A and C are not correct.

Moreover, 'If a function f(x) has period P, then the function cf(bx) will have period $\frac{P}{|b|}$ .

Also, form the figure, we see that the period of the graphed function is $\pi$ .

Since, $y=\tan (x)$ have period $\pi$ .

So, function in option B will have period $\frac{\pi}{2}$ , which is not possible.

<em>Further, function in option D have period $\pi$ .</em>

Thus, the equation of the graphed function is, $y=\tan (x-\pi)+2$ .

7 0

2 years ago

Read 2 more answers

Coordinates, gradient and tangent work (see image).

Ivenika [448]

Answer:

a) $P(x,2x^2-5),\ Q(x+h,2(x+h)^2-5)$

b) $4x+2h$

c) $4x$

Step-by-step explanation:

Given the curve

$y=2x^2-5$

a) If the x-coordinate of P is $x$ , then the y-coordinate is $2x^2-5,$ so point P has coordinates $(x,2x^2-5)$

If the x-coordinate of Q is $x+h$ , then the y-coordinate is $2(x+h)^2-5$ so point Q has coordinates $(x+h,2(x+h)^2-5)$

b) The gradient of the secant RQ is

$\dfrac{y_Q-y_P}{x_Q-x_P}\\ \\=\dfrac{(2(x+h)^2-5)-(2x^2-5)}{(x+h)-x}\\ \\=\dfrac{2(x+h)^2-5-x^2+5}{x+h-x}\\ \\=\dfrac{2(x+h)^2-2x^2}{h}\\ \\=\dfrac{2x^2+4xh+2h^2-2x^2}{h}\\ \\=\dfrac{4xh+2h^2}{h}\\ \\=4x+2h$

c) If $h\rightarrow 0,$ then the gradient $4x+2h\rightarrow 4x$

5 0

2 years ago