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2 years ago

Which of the following are exterior angles? Check all that apply.

Mathematics

2 answers:

Helen [10]2 years ago

7 0

An exterior angle of a triangle is an angle formed by one side of the triangle and the extension of an adjacent side of the triangle.

FACTS:

Every triangle has 6 exterior angles, two at each vertex.
Notice that the "outside" angles that are "vertical" to the angles inside the triangle are NOT called exterior angles of a triangle.

1. Angles 1, 5 and 6 are inteior angles of the given triangle.

2. Angle 3 is vertical to the interior angle 5.

3. Angles 2 and 4 are exterior angles of the triangle.

Answer: correct options are A and B.

alex41 [277]2 years ago

7 0

Answer:

A. $\angle 2$

B. $\angle 4$

Step-by-step explanation:

Exterior angle: Exterior angle is that angle which is formed by one side and extended adjacent side of the triangle at out side .

In other words,

We can say that

Exterior angle is that angle which form linear pair with one of the interior angles of the triangle.

It means sum of exterior angle and one of interior angle =180 degrees.

By definition of exterior angle

Angle 4 and angle 2 are exterior angles.

Hence, option A and B are true.

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Please help me with this question #8

MA_775_DIABLO [31]

Think of sqrt(2) as a variable.

3x - x = 2x

If x = sqrt(2), then answer is 2sqrt(2)

6 0

1 year ago

A maths class has equal numbers of boys and girls. Eight of the girls left early to play in a netball match. This left 3 times a

irina [24]

Step-by-step explanation:

x = boys / y = girls / s = total number of students

x + y = s

3x + y - 8 = s

Maybe someone can improve upon this because this is all I know. Not the answer btw ^^^

4 0

2 years ago

Determine whether the lines are parallel, intersect, or coincide. x-5y=0, y+1=1/5(x+5)

MAXImum [283]

Answer-

The lines are two coinciding lines or the same lines.

Solution-

The given line equations are

the first one,

$\Rightarrow x-5y=0$

the second one,

$\Rightarrow y+1=\dfrac{1}{5}(x+5)\\\\\Rightarrow 5y+5=x+5\\\\\Rightarrow 5y=x\\\\\Rightarrow x-5y=0$

As we know two line equations $A_1x+B_1y+C_1=0$ and $A_2x+B_2y+C_2=0$ will be,

Parallel if, $\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}$
Coincide if, $\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}$
Intersect if, $\dfrac{A_1}{A_2}\neq \dfrac{B_1}{B_2}$

As here,

$\Rightarrow \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}$

$\Rightarrow \dfrac{1}{1}=\dfrac{-5}{-5}$

(C₁ and C₂ aren't considered as they are 0)

Therefore, the lines are two coinciding lines or the same lines.

4 0

2 years ago

Cindi is planting a rectangular flower bed with 40 orange flower and 28 yellow flowers. She wants to plant them so that each row

Vilka [71]

Answer: 17 rows, 7 of yellow flowers and 10 of orange flowers.

Step-by-step explanation:

We have 40 orange flowers

we have 28 yellow flowers.

The total number of flowers is 40 + 28= 68

Now, we want to find the maximal comon factor between 28 and 40 (that will be the number of flowers in each row)

for this, we took the smallest number and find its factors, and then we see if those factors are also of the greater number.

28/1 = 28 ----> 40/28 is not integer, so 28 is not a factor of 40.

28/2 = 14 ----> 40/14 is not integer, so 14 is not a factor of 40.

28/3 is not integer.

28/4 = 7 ----> 40/7 is not integer, so 7 is not a factor of 40.

28/5 is not integer.

28/6 is not integer.

28/7 = 4, 40/4 = 10, so 4 is a factor of both 28 and 40.

Then the maximum number of flowers that we can put in each row is 4.

this means that we have:

28/4 = 7 rows of yellow flowers (with 4 flowers each)

40/4 = 10 rows of orange flowers (with 4 flowers each)

a total of 17 rows.

3 0

2 years ago

The diagram shows a square (6x -1)cm (4x+6)cm find the length of the side of the square

sammy [17]

Answer:

3.5 cm

Step-by-step explanation:

6x-1=4x+6

6x-4x=1+6

2x=7

x=7÷2

x=3.5

I hope my answer will help you and i guess it's correct

7 0

1 year ago