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Natalija [7]
2 years ago
7

Triangle RST was dilated by a scale factor of One-half. The image, triangle R'S'T', is an isosceles triangle, with each leg meas

uring 8 units.
Point Q is the center of dilation. Isosceles triangle R S T was dilated to smaller triangle R prime S prime T prime. Sides R S and R T are 8 units long.

What is the length of a leg of the pre-image, triangle RST?

4 units
8 units
16 units
20 units
Mathematics
2 answers:
andrew11 [14]2 years ago
8 0

Answer:

The length side of the pre-image is 16 units

Step-by-step explanation:

we know that

The length side of the image is equal to the length side of the pre-image multiplied by the scale factor

or

The length side of the pre-image is equal to the length side of the image divided by the scale factor

in this problem we have that

The scale factor is 1/2

The length side of the image is 8 units

therefore

8/(1/2)=16 units

The length side of the pre-image is 16 units

DiKsa [7]2 years ago
4 0

Answer:

16

Step-by-step explanation:

just took the test (:

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Answer:

\large\boxed{y=\dfrac{2}{3}}

Step-by-step explanation:

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1. multiply 250 by 10% (250 * .1= 25)
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One of the solutions to x2 − 2x − 15 = 0 is x = −3. What is the other solution?
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6 0
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yKpoI14uk [10]
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1 year ago
Segment AB falls on line 2x − 4y = 8. Segment CD falls on line 4x + 2y = 8. What is true about segments AB and CD? They are perp
Alisiya [41]

Answer:

They are perpendicular because they have slopes that are opposite reciprocals of −2 and one half.

Step-by-step explanation:

This is because x = -2 and half of -2 is 1

when we use CD line and x2 we find 8x+4y=16 when added to 2x -4y=8 would equal 10x+4y = 2 1/2 xy = 16

When we use for AB line we see they are perpendicular 2 1/2 x 2 = 5 -4y = 8 shows y to be -2 and the 1/2 line leaves -2 1/2 and x also is 2 1/2.

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1 year ago
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