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Natalija [7]
2 years ago
7

Triangle RST was dilated by a scale factor of One-half. The image, triangle R'S'T', is an isosceles triangle, with each leg meas

uring 8 units.
Point Q is the center of dilation. Isosceles triangle R S T was dilated to smaller triangle R prime S prime T prime. Sides R S and R T are 8 units long.

What is the length of a leg of the pre-image, triangle RST?

4 units
8 units
16 units
20 units
Mathematics
2 answers:
andrew11 [14]2 years ago
8 0

Answer:

The length side of the pre-image is 16 units

Step-by-step explanation:

we know that

The length side of the image is equal to the length side of the pre-image multiplied by the scale factor

or

The length side of the pre-image is equal to the length side of the image divided by the scale factor

in this problem we have that

The scale factor is 1/2

The length side of the image is 8 units

therefore

8/(1/2)=16 units

The length side of the pre-image is 16 units

DiKsa [7]2 years ago
4 0

Answer:

16

Step-by-step explanation:

just took the test (:

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Complete the steps in solving the quadratic function 7x – 9 = 7x2 – 49x by completing the square. –9 = 7x2 – x –9 + = 7(x2 – 8x
anzhelika [568]

Answer:

A) 56 . . . . . . the (negative) sum of -7 and -49

b) 112 . . . . . the product of 7 and 16

c) 16 . . . . . . the square of 8/2

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How can a translation and reflection be used to map HJK to LMN?
Furkat [3]
First hjk undergoes translation that make it goes upward. then they reflect to become lmn
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. En un concesionario de coches hay modelos de varios colores. Los rojos suponen 1 6 del total, los azules, 2 9 del total, y los
Sholpan [36]

Complete question :

En un concesionario de coches hay modelos de varios colores. Los rojos suponen 1/6 del total, los azules, 2/9 del total, y los blancos, 4/15 del total.

a)¿Cuál de esos colores es el más frecuente?

b) Si hay 40 coches azules, ¿cuántos hay en total?

Responder:

Coches blancos

180 coches

Explicación paso a paso:

Dado que:

Rojo = 1/6 del total

Azul = 2/9 del total

Blanco = 4/15 del total

Para determinar qué color es el más alto, convierta los valores en decimal:

1/6 = 0,166667

2/9 = 0,2222

15/4 = 0,26667

Por lo tanto;

4/15> 2/9> 1/6

Por tanto, los coches blancos son los que más

2.)

Sea Número total = x

Por lo tanto,

2/9 de x = 40

2x / 9 = 40

2x = 360

x = 180

Por tanto, hay 180 coches en total.

4 0
2 years ago
A playground measures 300 m × 170 m.Find the cost of planting grass on this at the rate of Rs 80 per hectare.​
Ierofanga [76]
<h2><u>Answer</u> :-</h2>

To find the cost of planting grass , we have to find area of the field.

Area of field = Length × Breadth

{= 300×170}

{=51000 sq. m}

Now convert into hectare.

1 hectare = 10000m sq.

51000 / 10000

So area field = 5.1 hectare sq.

Now cost = 5.1 x 0.80 p

{= 0.408 p}

<h2><u>___________</u></h2>
7 0
2 years ago
In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
FrozenT [24]

Answer: The length of segments between this point and the vertices of greater base are 7\frac{5}{7} and 18.

Step-by-step explanation:

Let ABCD is the trapezoid, ( shown in below diagram)

In which AB is the greater base and AB = 18 DC= 11, AD= 3 and BC = 7

Let P is the point where The extended legs meet,

So, according to the question, we have to find out : AP and BP

In Δ APB and Δ DPC,

∠ DPC ≅ ∠APB ( reflexive)

∠ PDC ≅ ∠ PAB    ( By alternative interior angle theorem)

And, ∠ PCD ≅ ∠ PBA  ( By alternative interior angle theorem)

Therefore, By AAA similarity postulate,

\triangle APB\sim \triangle D PC

Let, DP =x

⇒ \frac{3+x}{18} = \frac{x}{11}

⇒  33 +11x = 18x

⇒ x = 33/7= 4\frac{5}{7}

Thus, PD= 4\frac{5}{7}

But, AP= PD + DA

AP= 4\frac{5}{7}+3 =7\frac{5}{7}

Now, let PC =y,

⇒ \frac{7+y}{18} = \frac{y}{11}

⇒ 77 + 11y = 18y

⇒ y = 77/7 = 11

Thus, PC= 11

But, PB= PC + CB

PB= 11+7 = 18



7 0
2 years ago
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