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disa [49]
2 years ago
8

The perimeter of a square is represented by the expression 32x - 12.8. Draw a square to represent this situation and label its s

ide lengths. Then write three equivalent expressions for the perimeter.

Mathematics
1 answer:
Hoochie [10]2 years ago
3 0

Answer:

Step-by-step explanation:

Given that: The perimeter of a square is: 32x - 12.8

As we all know that, the formula to find the perimeter of a square is:

Sum of the 4 side = 4* length of the side  

=> the length of 1 side: The perimeter of a square  / 4

In this situation, we have length of 1 side side is:

(32x - 12.8) / 4

= 32/4x - 12.8/4

= 8x - 3.2

The 1st equivalent expressions for the perimeter: 4 *(8x - 3.2)

The 2nd equivalent expressions for the perimeter: (8x - 3.2) + (8x - 3.2)  + (8x - 3.2)  + (8x - 3.2)

The 3rd equivalent expressions for the perimeter: 2*(8x - 3.2) + 2*(8x - 3.2)

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Over the course of a year,a tractor-trailer commutes 160,000 miles across America.Assuming a trucker changes his tires every 40,
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160,000 - 40,000= 120,000/4 = 3 sets of new tires in the first year and 4 every consecutive year.
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2 years ago
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Rectangle ABCD is translated (x + 2 y - 3) and then rotated 180° about the origin. Complete the table to show the locations of A
katen-ka-za [31]

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A

Step-by-step explanation:

4 0
2 years ago
The first terms of an infinite geometric sequence, Un are 2, 6, 18, 54... The first terms of a second infinite geometric sequenc
gladu [14]

Answer:

r = 9 and m = 112

Step-by-step explanation:

\sum_{k=1}^{225}W_{k}=\sum_{k=0}^{m}4r^{k}

Write W in terms of U and V.

\sum_{k=1}^{225}(U_{k}+V_{k})=\sum_{k=0}^{m}4r^{k}\\\sum_{k=1}^{225}U_{k}+\sum_{k=1}^{225}V_{k}=\sum_{k=0}^{m}4r^{k}

Define U and V using geometric series formula.

\sum_{k=1}^{225}2(3)^{k-1}+\sum_{k=1}^{225}2(-3)^{k-1}=\sum_{k=0}^{m}4r^{k}

Use sum of geometric series formula.

2(\frac{1-(3)^{225}}{1-3})+2(\frac{1-(-3)^{225}}{1-(-3)})=4(\frac{1-(r)^{m+1}}{1-r})

Simplify.

-1(1-3^{225})+\frac{1+3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-1+3^{225}+\frac{1}{2}+\frac{3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-\frac{1}{2}+\frac{3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3^{226}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{-1+3^{226}}{8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-3^{226}}{-8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-9^{113}}{1-9}=4(\frac{1-(r)^{m+1}}{1-r})

Therefore, r = 9 and m = 112.

8 0
2 years ago
What is the slope of the line defined by the parametric equations x=-2+4t and y=1+4t ?
LekaFEV [45]

Answer:

The value of slope m = -1

Step-by-step explanation:

x = -2 + 4t

and y = 1 + 4t

Solving the both equations

x +2 = 4t

=> t = (x+2)/4     eq(1)

y-1 = 4t

=> t = (y-1)/4      eq(2)

Putting eq(1) = eq(2) as left hand side of both equations are same

(x+2)/4 = (y-1)/4

Cross multiplying

4(x+2) = 4(y-1)

4x + 8 = 4y -4

4x +4y = -4 -8

4x + 4y = -12

4(x+y) = -12

x+y = -12/4

x+y = -3

y = -x -3

The slope intercept form of line is:

y = mx + b

where m is the slope. Comparing with y = -x-3

The value of slope m = -1

8 0
2 years ago
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