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2 years ago

8

A can of juice has a diameter of 6.6 centimeters and a height of 12.1 centimeters and a height of3 what is the volume of the sto

rage cylinder

1 answer:

andreyandreev [35.5K]2 years ago

4 0

Answer:

Volume of the juice can = $413.75cm^3$

Step-by-step explanation:

Given:

$Diameter= 6.6 cm$

$Radius= 6.6/2=3.3 cm$

$Height= 12.1 cm$

Volume of a cylinder= $\pi *r^2*h$

: $\pi =\frac{22}{7} =3.14$

Volume of the cylindrical Juice can = $3.14*3.3*3.3*12.1$

= $413.75cm^3$

So, the volume of the juice can is $413.75cm^3$

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Answer:

2,7204x 10^9

Step-by-step explanati

2870000000-

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2 years ago

Among a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in

Hitman42 [59]

Answer:

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) We can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval

(3) A survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

Step-by-step explanation:

We are given that a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in school, 48% said they decided not to go to college because they could not afford school.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of Americans who decide to not go to college = 48%

n = sample of American adults = 331

p = population proportion of Americans who decide to not go to

college because they cannot afford it

<em>Here for constructing a 90% confidence interval we have used a One-sample z-test for proportions.</em>

<em />

<u>So, 90% confidence interval for the population proportion, p is ;</u>

P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level

of significance are -1.645 & 1.645}

P(-1.645 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.645) = 0.90

P( $-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < $\hat p-p$ < $1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

P( $\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.90

<u>90% confidence interval for p</u> = [ $\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.48 -1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } }$ , $0.48 +1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } }$ ]

= [0.4348, 0.5252]

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) The interpretation of the above confidence interval is that we can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval.

3) Now, it is given that we wanted the margin of error for the 90% confidence level to be about 1.5%.

So, the margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$

$0.015 = 1.645 \times \sqrt{\frac{0.48(1-0.48)}{n} }$

$\sqrt{n} = \frac{1.645 \times \sqrt{0.48 \times 0.52} }{0.015}$

$\sqrt{n}$ = 54.79

n = $54.79^{2}$

n = 3001.88 ≈ 3002

Hence, a survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

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2 years ago

The point (Negative StartFraction StartRoot 2 EndRoot Over 2 EndFraction, StartFraction StartRoot 2 EndRoot Over 2 EndFraction)

Ierofanga [76]

Answer:

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Step-by-step explanation:

The given point is :

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This point is in the second quadrant.

This means:

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2 years ago

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lesantik [10]

The volume of the cone with radius r=14 cm and height h=15 cm is,
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Each day 40 cm^3 is subtracted from the volume. So the volume of honey left after [d] number of days would be the starting volume minus 40 times number of days passed.
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It asks when the volume will be empty, The volume left is zero after how many days?
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2 years ago

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Una compañía encuentra que su utilidad esta dada por R=2pe^-0.1p cuando au producto esta cotizado en p dolares por unidad. Encue

e-lub [12.9K]

Answer:

6.065; 7.358 ; 6.694

Step-by-step explanation:

Given that, profit is quoted using the function :

R = 2pe ^ -0.1p

(a)

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R = 2(5)e^(-0.1*5)

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R = 6.065

B)

When price 'p' = $10

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R = 20e^(-1)

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R = 7.358

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When price 'p' = $15

R = 2(15)e^(-0.1*15)

R = 30e^(-1.5)

R = 30 * 0.2231301

R = 6.694

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2 years ago