I can't really answer this problem if we focus only on the given information. However, I found a similar problem to this with a given diagram. This is shown in the picture attached. As you can observe, two arcs have equal measures of 65° and two have measures of 115°. Thus, the congruent arcs are:
<em>EH = HG and EF = GF.</em>
By definition, the arc length is given by:
arc = (theta) * (R)
Where,
theta: central angle
R: radius
Substituting values we have:
arc = (π / 5) * (2.8)
Rewriting we have:
arc = ((3.14) / 5) * (2.8)
arc = 1.7584 cm
Round to the hundredth:
arc = 1.76 cm
Answer:
the arc length is:
arc = 1.76 cm
You have :
--------------
DE arc = ( pi ) ( AD ) ( 2.36 radians / 2 pi radians ) = ( 2/3 ) ( AB ) ( 2.36 radians / 2 )
DE arc = ( 2/3 ( AB ) ( 1.18 radians )
BC arc = ( pi ) ( AB ) ( 1.18 radians / 2 pi radians )
BC arc = ( AB ) ( 0.59 radians )
BC arc / DE arc = ( AB ) ( 0.59 radians ) / ( 2/3 ) ( AB ) ( 1.18 radians )
BC arc / DE arc = ( AB ) ( 0.59 rad ) / ( 2/3 ) ( AB ) ( 1.18 rad )
BC arc / DE arc = ( 3/2 ) ( .59 rad / 1.18 rad ) = 3/4 <-------
