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agasfer [191]
2 years ago
6

Please Help Me! It would be very much appreciated!

Mathematics
2 answers:
skad [1K]2 years ago
7 0
The answer should be B) an=3+5(n-1)

hope i helped :)
Elan Coil [88]2 years ago
5 0
If i’m doin this right the answer should be B
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2. ½ of a group of chickens tried to cross the road. Only ¾ of those chickens made it to the other side. What fraction of the or
ArbitrLikvidat [17]
Let me help you visualize this one.

Let's say we have 12 chickens.

OOOOOOOOOOOO

We divide this group in half (1/2 who tried to cross the road.)

OOOOOO

And here, we need to get 3/4 of the 6 left.

3/4 can be represented as 0.75 of 1.

6 times 0.75 equals to 4.5.

OOOOC (Woah, that chicken is split in half!)

What fraction is 4.5 of the original amount?

Well, that's for you to find out! Good luck in solving this question.
3 0
1 year ago
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Stores often mark up items each year to cover inflation. Last year, a CD at Juan’s Tunes cost $12.95. This year, the cost was ma
Ratling [72]
4*12.95*1.08-4*12.95*1.08*.10
if u buy 4
7 0
1 year ago
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If f(1) = 0 what are all the roots of the function f(x)=x^3+3x^2-x-3 use the remainder theorem.
ArbitrLikvidat [17]

Solution:

As we are given that f(1) = 0 .

It mean that (x-1) is one of the factor of the given equation.

Remainder theorem can be applied as below:

\frac{(x^3+3x^2-x-3)}{(x-1)}=\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}\\ \\\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}=\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)} \\\\\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)}=\frac{(x^2+4x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+4x+3)(x-1)}{(x-1)} =\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  =\frac{(x-1)(x+3)(x+1)}{(x-1)}

Hence the factors are (x-1),(x+3) and (x+1).

Hence the correct option is B.

5 0
2 years ago
Read 2 more answers
A restaurant serves custom-made omelets, where guests select meat, cheese, and vegetables to be added to their omelet. There are
kondor19780726 [428]

Answer: The number of different combinations of 2 vegetables are possible = 15 .

Step-by-step explanation:

In Mathematics , the number of combinations of selecting r values out of n values = ^nC_r=\dfrac{n!}{r!(n-r)!}

Given : Number of available vegetables = 6

Then, the number of different combinations of 2 vegetables are possible will be :

^6C_2=\dfrac{6!}{2!(6-2)!}=\dfrac{6\times5\times4!}{2\times4!}=15

Hence , the number of different combinations of 2 vegetables are possible = 15 .

5 0
1 year ago
Solve the inequality for x, assuming that a, b, and c are positive constants.
Fynjy0 [20]
A(bx − c) ≥ bc, implies (bx − c) ≥ bc /a  and then  bx  ≥ bc/a + c, x<span>≥ c/a +c/b
so the solution is </span><span>3. [c/a + c/b, infinity)</span>
4 0
1 year ago
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