Answer:
From the frequency table, let's calculate the row total.
Row total for phone call = 19 + 9 = 28
Row total for no phone call = 8 +6 = 14
To calculate their respective row relative frequencies, let's use:
Row relative freq = 
Now, the two-way frequency table will be computed as:
For phone call:
Desirable behavior = 
≈0.69
Undesirable behaviour = 
≈0.32
No phone call:
Desirable behaviour = 
≈ 0.57
Undesirable behaviour = 
≈ 0.43
The complete two-way table is attached.
Answer:
The smallest bag that has enough food to feed his bag for one month
= 3.6 kilogram
Step-by-step explanation:
The quantity of dry food Ray feeds his dog = 0.12 kilogram
So the quantity of food he feeds his dog in one month
= 0.12 × 30 ∵ since 1 month = 30 days
= 3.6 kilogram
The smallest bag that has enough food to feed his bag for one month
= 3.6 kilogram
Answer:
f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 4 meters from the ground
Step-by-step explanation:
The function is a quadratic where t is time and f(t) is the height from the ground in meters. You can write the function f(t) = 4t2 − 8t + 8 in vertex form by completing the square. Complete the square by removing a GCF from 4t2 - 8t. Take the middle term and divide it in two. Add its square. Remember to subtract the square as well to maintain equality.
f(t) = 4t2 − 8t + 8
f(t) = 4(t2 - 2t) + 8 The middle term is -2t
f(t) = 4(t2 - 2t + 1) + 8 - 4 -2t/2 = -1; -1^2 = 1
f(t) = 4(t-1)^2 + 4 Add 1 and subtract 4 since 4*1 = 4.
The vertex (1,4) means at a minimum the roller coaster is 4 meters from the ground.
- f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 2 meters from the ground
- f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 4 meters from the ground
- f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 1 meter from the ground
- f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 4 meters from the ground
First, you need to determine the resultant force and its angle. This one is real easy, since you only have one (x) and one (y) component. X = 300 and Y = 480
<span>1) sqrt (300^2 + 480^2) = ? (round your answer) </span>
<span>2) tanθ = y/x Solving for θ: θ = tan^-1(y/x): θ = ? (round your answer) </span>
<span>Now, you should have a resultant force value and its angle, from zero, in the first quadrant and between the Y and N axes. Draw yourself a diagram showing all of the axes, the resultant and the angles. You're going to have to do some very easy math to determine the angles between the Y and N axes and the resultant. Call these new angles α and β. α is the angle between N and the resultant and β is the angle between T and the resultant. Hint: one of them is 28 deg. </span>
<span>Once you've gotten those figured, the Y and N axes become your new axis, ignore the X and Y. Find the X and Y components of the resultant (again). ? * cos(α) = 500 and ? * sin(β) = 266 (round your answers)</span>
