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1 year ago

2 sandwiches and 3 croissants costs £11.

Mathematics

1 answer:

valentina_108 [34]1 year ago

5 0

Answer:

The price of a sandwich is £2.5 and the price of a croissant is £2

Step-by-step explanation:

Let s be the number of sandwiches and c be the number of croissants

Then according to given statements the equations will be:

$2s+3c = 11\ \ \ \ \ \ \ Eqn\ 1\\3s+6c =19.50\ \ \ Eqn\ 2$

Multiplying equation 1 by 2 and subtracting equation 2 from the new equation

$2(2s+3c) = 11*2\\4s+6c = 22$

Now

$4s+6c-(3s+6c) = 22-19.50\\4s+6c-3s-6c = 2.5\\s = 2.5$

Putting s=2.5 in equation 1

$2(2.5)+3c = 11\\5+3c = 11\\3c = 11-5\\3c = 6\\\frac{3c}{3} = \frac{6}{3}\\c = 2$

Hence,

The price of a sandwich is £2.5 and the price of a croissant is £2

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The claim is not fair because:

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Step-by-step explanation:

The probaility of an event is defined as the number of favorable outcomes divided by the number of total possible events.

P (event E) = number of outcomes for event E / number of possible events

1. As first step, you may draw a table to find the sample space (set of all possible outcomes).

Sample space

The results of the rolling two dice are summarized in this table:

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1 (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

2 (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

3 (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

4 (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

5 (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

6 (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

2.Now, in that table, you can observe:

The results (3,3) and (6,6) are highlited.

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c) Number of outcomes for the event rolling two 3s (3,3): 1

3) Next, you can calculate the probabilities:

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4). The curved pit is shifted 2 units down,

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