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RUDIKE [14]
2 years ago
6

Adventure Play sells an mp3 player for $18.00 and charges $3.25 per song. King Music sells a player for $23.00 and charges $2.00

per song. For how many songs will the cost be the same?
Mathematics
1 answer:
Rus_ich [418]2 years ago
4 0
An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or …show more content… 
An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or half-moon status because at least 50 percent of its surface was illuminated. In the following nights, the Moon displayed characteristics of waxing gibbous as the light continued to grow across the moon’s surface from right to left. The Moon was nearing closer to the full moon phase on November 14th as only a very small dark shadow was visible on the left side. 
The Moon takes 27.3 days (sidereal month) to complete its actual orbit around the Earth. Like the Sun, the Moon rises in the east and sets in the west each day. 
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The volume inside of a sphere is V=4πr33 where r is the radius of the sphere. Your group has been asked to rearrange the formula
Semmy [17]

Answer:

Therefore,

r=\sqrt[3]{\frac{3V}{4\pi }}

is the required r

Step-by-step explanation:

Given:

Volume of inside of the sphere is given as

V=\frac{4}{3} \pi r^{3}

where r is the radius of the sphere

To Find:

r =?

Solution:

We have

V=\frac{4}{3} \pi r^{3}   ......Given

3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}

Therefore,

r=\sqrt[3]{\frac{3V}{4\pi }}

is the required r

5 0
2 years ago
The moon is 384,403 km from the Earth. Estimate how many quarters laid end to end it would take to reach the moon if a quarter h
Kryger [21]
$16.96  16 times 6% is .96
7 0
2 years ago
Read 2 more answers
On the drawing for a house plan, the master bedroom is rectangular and has dimensions of 2.25 inches by 2.5 inches. If the scale
satela [25.4K]

The answer is 16 metric units by the quarter mile

8 0
1 year ago
A town has a population of 5000 and grows 3.5% every year. To the nearest tenth of a year, how long will it be until the populat
oksano4ka [1.4K]

Answer:

Step-by-step explanation:

This is an exponential function. In order to find the answer to the question, we need to first determine what the equation is that models this information. The standard form for an exponential function is

y=a(b)^x where a is the initial value and b is the growth/decay rate. If the starting population is 5000, then

a = 5000

If the population is growing, that means that it retains 100% of the initial population and is added to by another 3.5%. So in a sense the population grows 100% + 3.5% = 103.5% or, in decimal form, 1.035. So

b = 1.035

Our function is

y=5000(1.035)^x where y is the ending population and x is the number of years it takes to get to that ending population. We want to know how long, x, it will be til the population reaches 7300, y.

7300=5000(1.035)^x and we need to solve for x. The only way to do that is by using logs. I'll use natural logs for this.

Begin by dividing both sides by 5000 to get

1.46=1.035^x and take the natural log of both sides:

ln(1.46)=ln(1.035)^x

The power rule for natural logs is that we can now bring the exponent down in front of the ln to get:

ln(1.46)=xln(1.035) To solve for x, we now divide both sides by ln(1.035):

\frac{ln(1.46)}{ln(1.035)}=x

Do that division on your calculator and get that

x = 11.0 years.

That means that 11 years after the population was 5000 it will be expected to reach 7300 (as long as the growth rate remains 3.5%)

5 0
2 years ago
Given log Subscript 4 Baseline 3 almost-equals 0.792 and log Subscript 4 Baseline 21 almost-equals 2.196, what is log Subscript
defon

Answer:

Step-by-step explanation:

The following is the logarithm quotient rule:

log_{c}{a / b} = log_{c}{a} - log_{c}{b}

Plugging in the values we have above gives us the following:

log_{4}{21 / 3} = log_{4}{21} - log_{4}{3}

log_{4}{7} = 2.196 - 0.792

log_{4}{7} = 1.404

6 0
2 years ago
Read 2 more answers
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