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goldenfox [79]
2 years ago
12

Fill in the gaps in the arithmetic sequence -3, _ ,_ , _, _, _ 12

Mathematics
1 answer:
lord [1]2 years ago
8 0

Answer:

  -0.5, 2, 4.5, 7, 9.5

Step-by-step explanation:

The given terms are 6 apart, so the common difference is 1/6 of their difference:

  d = (12 -(-3))/6 = 15/6 = 5/2 = 2.5

Add 2.5 to each term to get the next one. Then the sequence is ...

  -3, <u>-0.5</u>, <u>2.0</u>, <u>4.5</u>, <u>7.0</u>, <u>9.5</u>, 12

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T varies inversely as the square root of u.<br>t = 3 when u = 4.<br>Find t when u = 49.​
RoseWind [281]

Answer:

t = \frac{6}{7}

Step-by-step explanation:

Given that t varies inversely as the square root of u then the equation relating them is

t = \frac{k}{\sqrt{u} } ← k is the constant of variation

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How do you use a number line to solve 235+123
Novosadov [1.4K]
<span>Number line refers to a mathematical process of solving the equation with the use of lines.
=> 235 + 123
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Then from zero start counting the total number to the line you stopped when adding 123 to 235.

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2 years ago
How many terms in the arithmetic sequence(2,4,6,8....) will give sum of 600
andriy [413]

Answer:

  24 terms

Step-by-step explanation:

The sum of an arithmetic sequence is the average of the first and last terms, multiplied by the number of terms. The last term is given by ...

  an = a1 + (n-1)d

We have a sequence with first term a1 = 2 and common difference d = 2. So the last term is ...

  an = 2+ 2(n -1) = 2n

Then the average of first and last terms times the number of terms is ...

  Sn = 600 = n(2 + 2n)/2 = n(n+1) . . . . . . close to n²

We can solve the quadratic in n, or we can estimate the value of n as the integer just below the square root of 600.

  √600 ≈ 24.5

so we believe n = 24.

_____

<em>Check</em>

  S24 = 24·25 = 600 . . . . . . as required.

8 0
1 year ago
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