Answer:
For the sampling distribution,
a) Mean = μₓ = 55.0 students.
b) Standard Deviation = 1.8 students.
Step-by-step explanation:
The complete Question is attached to this solution.
The Central limit theorem explains that for the sampling distribution, the mean is approximately equal to the population mean and the standard deviation of the sampling distribution is related to the population standard deviation through
σₓ = (σ/√n)
where σ = population standard deviation = 4
n = sample size = 5
Mean = population mean
μₓ = μ = 55 students.
Standard deviation
σₓ = (σ/√n) = (4/√5) = 1.789 students = 1.8 students to 1 d.p
Hope this Helps!!!
Answer:
For this case assuming that the random variable is X
And replacing n = 24 we got:
And we notate the distribution we got: 
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
For this case assuming that the random variable is X
And replacing n = 24 we got:
And we notate the distribution we got:
A) The result of adding the two equations is
.. (2.5y +3x) +(5x -2.5y) = (27) +(5)
.. 8x = 32 . . . . . . . . . . . . . . . . . . . . . . . your 2nd selection
b) The solution to the system is (4, 6), your 4th selection.
.. This is the only choice with x=4, the solution to part (a).
Answer:
Solutions:
Step-by-step explanation:
Expanding the factored form:
Factoring the second-degree polynomial:
This is true for
