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Alekssandra [29.7K]
2 years ago
7

Eliza started her savings account with $100. Each month she deposits $25 into her account. Determine the average rate of change

in Eliza's account from the 2nd month to the 10th month. Show all work for full credit.
Mathematics
1 answer:
Afina-wow [57]2 years ago
6 0
First, lets create a equation for our situation. Let x be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>f(x)=25x+100
<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is: \frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1} }. So lets replace the values in our formula to find the average of our function:
\frac{25(10)+100-[25(2)+100]}{10-2}
\frac{350-150}{8}
\frac{200}{8}
25

We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
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Step-by-step explanation:

<h2><u>A:</u></h2>

We know that the total investment period is 1 year, then since A started, A invested Rs 26,000.

<u>Now, since A has been working for 12 months, this is where the effective investment comes in:</u>

A effective investment = Rs 312,000

<h2><u>B:</u></h2>

<u>Then after 3 months, B joined, so:</u>

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C investment period = 9 months - x certain amount of months

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<u></u>

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