Answer:
a) This is an Observational Study because in this kind of study investigators observe subjects and measure variables of interest without assigning treatments to the subjects. Here, the Gilham et al. (2005) studied two different groups where no treatment or intervention was done. These groups were independent of each other.
b) proportions of children with significant social activity in children with acute lymphoblastic leukemia = 1020/1272 = 0.80
proportions of children with significant social activity in children without acute lymphoblastic leukemia = 5343/6238 = 0.86
c) Odds ratio can be calculated using the following formula:
OR= \frac{a/b}{c/d}
where: a - Number in exposed group with positive outcome(here this means number of children with significant social activity associated with acute lymphoblastic leukemia)
b- Number of children without social activity having with acute lymphoblastic leukemia
c- Number of children with social activity having without acute lymphoblastic leukemia
d- Number of children without social activity having without acute lymphoblastic leukemia
OR= \frac{1020/252}{5343/895}
OR= 0.6780
d) The 95% confidence interval of this Odds Ratio is 0.5807 to 0.7917.
e) Since the odds ratio lies in this confidence interval indicate that the amount of social activity is associated with acute lymphoblastic leukemia. The children with more social activity have a higher occurrence of acute lymphoblastic leukemia.
The answer is B
a1= 13;an-1+2
Answer:
(a) The probability of more than one death in a corps in a year is 0.1252.
(b) The probability of no deaths in a corps over 7 years is 0.0130.
Step-by-step explanation:
Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.
The random variable
.
The probability function of a Poisson distribution is:

(a)
Compute the probability of more than one death in a corps in a year as follows:
P (X > 1) = 1 - P (X ≤ 1)
= 1 - P (X = 0) - P (X = 1)

Thus, the probability of more than one death in a corps in a year is 0.1252.
(b)
The average deaths over 7 year period is: 
Compute the probability of no deaths in a corps over 7 years as follows:

Thus, the probability of no deaths in a corps over 7 years is 0.0130.
Check the picture below.
now, bear in mind that, there are 60minutes in 1 degree, so 23' is just 23/60 degrees or about 0.38 degrees.
and 29' is just 29/60 degrees or about 0.48 degrees.
so 16°23' is about 16.38°, and 49°29' is about 49.48°

make sure your calculator is in Degree mode.
Answer:
9 and 2/5 gallons
Step-by-step explanation:
34 x 9 gallons = 306 miles
14 / 34 = 4/10 of the gallons
4/10 simplified = 2/5
Answer: 9 2/5