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Amanda [17]
2 years ago
13

Two production lines produce the same parts per week of which 100 are defective. Line 2 produces 2,000 parts per week of which 1

50 are defective. If you choose a part randomly from the stock what is the probability it is defective? If it is defective what is the probability it part. Line 1produces 1,000 produced by line 1?
Mathematics
1 answer:
Vikentia [17]2 years ago
5 0

Answer:

(a) 0.0833 or 8.33%

(b) 0.40 or 40%

Step-by-step explanation:

Parts line one (n1) = 1,000 parts

Defects line one (d1) = 100 parts

Parts line two (n2) = 2,000 parts

Defects line two (d2) = 150 parts

Total number of parts (n) = 3,000 parts

a. Probability of a randomly selected part being defective:

P(d) = \frac{d_1+d_2}{n_1+n_2}=\frac{100+150}{1,000+2,000}\\P(d) =0.0833=8.33\%

The probability is 0.0833 or 8.33%

b. Probability of a part being produced by line one, given that it is defective:

P(1|d)=\frac{P(1\cap d)}{P(1\cap d)+P(2\cap d)}\\P(1|d)=\frac{\frac{100}{3,000} }{\frac{100}{3,000}+\frac{150}{3,000}}\\P(1|d)=0.4 = 40\%

The probability is 0.40 or 40%.

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BigorU [14]

Answer:

a:  Sample mean: 20, Sample standard deviation: 1.732

b:  19.13 <µ < 20.87

c:  18.84< µ < 21.16

d:  as the confidence level increases, the interval becomes wider

Step-by-step explanation:

a:  Sample mean is found by adding up all the individual values of the sample, then dividing by the total number of values in the sample.  

Sample standard deviation is the square root of the variance

See the first attached photo for the calculations of these values.

We need to create a 80% confidence interval for the population.  Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.  

Look for the column on the t-distribution chart that has "area in two tails" of 0.20 (80%), and row 7 (degree of freedom)

The t-value is 1.415

See the second attached photo for the construction of the confidence interval

We need to create a 90% confidence interval for the population.  Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.  

Look for the column on the t-distribution chart that has "area in two tails" of 0.10 (90%), and row 7 (degree of freedom)

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See the third attached photo for the construction of the confidence interval

3 0
2 years ago
AC, DF, and GI are parallel. Use the figure to complete the proportion.
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4 0
2 years ago
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slavikrds [6]
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x:     -3    -2   -1   0   1   2
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g(x) = 4 sin(4x) - 3

The y-intercept occurs when x=0.
Therefore,
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g(x) has a y-intercept of
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Answer:
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2 years ago
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Kruka [31]

Answer:

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agasfer [191]

Answer:

Step-by-step explanation:

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7 0
2 years ago
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