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Vilka [71]
2 years ago
13

Triangle A C D is shown. Point B is near the center of the triangle. Angle A C D is bisected by line segment C B. Lines are draw

n from point B to points A and D to form 3 triangles within the larger triangle. Angle C B D is 125 degrees. The length of line segment A C is 52 centimeters and the length of line segment B D is 29 centimeters. If Line segment C B. bisects ∠ACD, what additional information could be used to prove ΔABC ≅ ΔDBC using SAS? Select three options. m∠ABC = 125° and AB ≅ DB ΔACD is isosceles with base AD ΔABD is isosceles with base AD CD = 52 cm AB = 29 cm
Mathematics
2 answers:
Vladimir [108]2 years ago
5 0

Answer:

A,B,D on edu :)

Step-by-step explanation:

astraxan [27]2 years ago
3 0

Answer:

m∠ABC = 125° and AB ≅ DB, ΔACD is isosceles with base AD, CD = 52 cm

Step-by-step explanation:

i just took the quiz

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hury!!!! Which system is equivalent to StartLayout Enlarged left-brace 1st row y = negative 2 x squared 2nd row y = x minus 2 En
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Answer:

3rd Option

Step-by-step explanation:

Which equation is the inverse of y = 7x2 – 10?

y = StartFraction plus-or-minus StartRoot x + 10 EndRoot Over 7 EndFraction

y = plus-or-minus StartRoot StartFraction x + 10 Over 7 EndFraction EndRoot

x = plus-or-minus StartRoot StartFraction x Over 7 EndFraction + 10 EndRoot

y = StartFraction plus-or-minus StartRoot x EndRoot Over 7 EndFraction plus-or-minus StartFraction StartRoot 10 EndRoot Over 7 EndFraction

8 0
2 years ago
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mark has a cabinet door in his kitchen with the dimensions shown below. he creates a scale drawing where the width of the cabine
laiz [17]

Answer:

h^{*} = 25\,in

Step-by-step explanation:

Let consider that door has a height of 5 feet and a width of 3 feet. The scale factor is:

n = \frac{15\,in}{3\,ft}

n = 5\,\frac{in}{ft}

The height of the cabinet is:

h^{*} = n \cdot h_{door}

h_{*} = \left(5\,\frac{in}{ft}  \right)\cdot (5\,ft)

h^{*} = 25\,in

6 0
2 years ago
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An unloaded truck and trailer, with the driver aboard, weighs 30{,}00030,00030, comma, 000 pounds. When fully loaded, the truck
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Answer:

1131 pounds.

Step-by-step explanation:

We have been given that an unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.

First of all, we will find weight of 18 tires by multiplying 18 by 3,300 as:

\text{Weight of tires of the fully loaded semi-truck}=18\times 3,300

\text{Weight of tires of the fully loaded semi-truck}=59,400

The weight of 26 pallets would be weight of 18 tires minus weight of unloaded truck.

\text{Weight of 26 pallets of cargo}=59,400-30,000

\text{Weight of 26 pallets of cargo}=29,400

Now, we will divide 29,400 by 26 to find average weight of one pallet of cargo.

\text{Average weight of one pallet of cargo}=\frac{29,400}{26}

\text{Average weight of one pallet of cargo}=1130.769230769

\text{Average weight of one pallet of cargo}\approx 1131

Therefore, the average weight of one pallet of cargo is approximately 1131 pounds.

3 0
2 years ago
The general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 = 0. The equation of this circle in standard form is
Ede4ka [16]

Answer:

The standard form of a circle is (x-h)^2 + (y-k)^2 = r^2 with (h,k) being the center of the circle and r being the radius. In this case the circle's equation in standard form is (x-2)^2 + (y+3)^2 = 18. Knowing this it's easy to see that the center of the circle (h,k) is (2,-3). Finally the radius is \sqrt{18} or in simplified terms, 3\sqrt{2}

Step-by-step explanation:

7 0
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The paired data below consist of the temperatures on randomly chosen days and the amount a certain kind of plant grew (in millim
rjkz [21]

Answer:

Step-by-step explanation:

Given is a paired data which consist of temperatures (X in mm) and growth

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x y xy x^2 y^2

     

62 36 2232 3844 1296

76 39 2964 5776 1521

50 50 2500 2500 2500

51 13 663 2601 169

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46 33 1518 2116 1089

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sx *sy      

r 0.195529176    

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7 0
2 years ago
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