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adoni [48]
2 years ago
9

Rutherford used positively charged particles to investigate the structure of the atom. The results surprised him, and he develop

ed the atomic model shown below. What surprising result is explained using this model? A few positive particles bounced back because they bounced off of the net formed by the ovals. A few positive particles bounced back because they were pushed away from the positive center. Most positive particles passed through because of the empty space between the outer edge and the center. Most positive particles passed through because they were attracted by the small particles moving around the center.
Mathematics
2 answers:
serious [3.7K]2 years ago
6 0

<u>Answer: </u>The correct statement is Most positive particles passed through because of the empty space between the outer edge and the center.

<u>Explanation:</u>

Ernest Rutherford gave an experiment known as Gold Foil Experiment.

In his experiment, he took a gold foil and then bombarded it with alpha particles which carry a positive charge of +2 units. He first thought that many of the particles will bounce back but to his surprise, many of them passed through, some of them deflected their path and a few of them bounced back.

From this he concluded that in an atom, there exist a small positive charge concentrated at the the center and an atom mostly consists of empty space.

Hence, the surprising statement is most positive particles passed through because of the empty space between the outer edge and the center.

mel-nik [20]2 years ago
3 0

The answer is (B): A few positive particles bounced back because they were pushed away from the positive center.

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Thomas is planning a trip to India. He is currently deciding which cities he would like to visit during his stay. The table belo
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2 years ago
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A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
denpristay [2]

Answer:

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

3 0
2 years ago
Kristen is 64 inches tall, and she stands 12 feet away from a streetlight. If she casts an 82-inch-long shadow, how tall is the
o-na [289]

Answer:

176.39 inches or

14.70 feet

Step-by-step explanation:

Consider the right triangle made by Kristen, ground and shadow.

This triangle has one leg as 64 inches.

Next consider the right triangle formed by street light, ground upto shadow tip.

The two triangles have common angle of elevation and also another angle as 90 degrees.

Hence the two triangles would be similar

Also if A is the angle made by hypotenuse of both triangles with the ground we have

tanx=\frac{64}{82}

This value also equals by bigger triangle as

tanx=\frac{h}{82+12(12)}=\frac{h}{226}

From these two we get

h = height of street light =\frac{226(64)}{82} =176.39

6 0
1 year ago
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Ksju [112]

Hi there!

~

R = \frac{2.1}{sin 67.5}

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(A)

Hope this helped you!

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