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morpeh [17]
2 years ago
13

The moon is 384,403 km from the Earth. Estimate how many quarters laid end to end it would take to reach the moon if a quarter h

as a diameter of 2.3 cm.
Mathematics
2 answers:
Kryger [21]2 years ago
7 0
$16.96  16 times 6% is .96
anyanavicka [17]2 years ago
3 0
First, convert 384,403km to cm which is 34840300000 then divide that by 2.3 to get 15147956521.73 but you would need to round up so the answer is about 15147956521.
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23.7 – y when y = 10
sveta [45]
10.7
23.7-10=10
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6 0
2 years ago
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triangle JKL is rotated 270 degrees counterclockwise about the origin to form triangle jkl what is the y-coordinate of point j
IRINA_888 [86]

The y-coordinate of point j' in the image triangle J'K'L' is -x coordinate of point j in the initial triangle JKL.

Step-by-step explanation:

The rule to apply here is that of 90° clockwise about the origin.

This is to say that: rotation 270° counterclockwise about the origin applies the same rule as rotation 90° clockwise about the origin.

In this case, If point j has coordinates (x,y) then after the rotation j' will have coordinates (y,-x)

So the y-coordinate of point j' in the image triangle J'K'L' is -x coordinate of point j in the initial triangle JKL.

Learn more

Rotation about the origin 270°:brainly.com/question/3382538

Keywords : triangle, rotated, origin, counterclockwise,y-coordinate

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5 0
1 year ago
Which congruence theorem can be used to prove △MLQ ≅ △NPQ?<br><br> AAS <br> SSS <br> ASA <br> SAS
storchak [24]
Answer: SSS

Proof:
In ΔMLQ and ΔNPQ,
MQ = NQ (given) S
Since Q is the midpoint of LP, by definition, LQ = QP (S)
LM = PN (given) S

∴ ΔMLQ ≡ ΔNPQ (SSS)
4 0
2 years ago
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Jeff lives 12 miles east of Stan. Jeff lives 16 miles north of Wei. What is the shortest distance that Stan and Wei can live fro
Greeley [361]
|  \
|     \ 
| 16  \
|         \
|______\
 12

Envision this as a right triangle, with one leg of 12 miles, and the other 16 miles. Solve using the Pythagorean Theorem a²+b²=c²:

12²+16²=c²
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7 0
2 years ago
Which transformations have been applied to the graph of f(x) = x2 to produce the graph of g(x) = –5x2 + 100x – 450? Select three
RSB [31]

Answer:

The graph of f(x) is shifted up 50 units

The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

Step-by-step explanation:

we have

f(x)=x^{2}

This is a vertical parabola open upward

The vertex is a minimum

The vertex is the origin (0,0)

g(x)=-5x^{2}+100x-450

This is a vertical parabola open downward

The vertex is a maximum

The first thing to note is that fx) is a parabola that opens up and g(x) opens down, so a reflection across the x-axis must have been applied.

Find the vertex of g(x)

Convert to vertex form

g(x)=-5x^{2}+100x-450

Complete the square

g(x)=-5(x^{2}-20x)-450

g(x)=-5(x^{2}-20x+100)-450+500

g(x)=-5(x^{2}-20x+100)+50

g(x)=-5(x-10)^{2}+50

The vertex is the point (10,50)

so

To translate the vertex of (0,0) to (10,50)

The rule of the translation is

(x,y) ------> (x+10,y+50)

That means ----> The translation is 10 units at right and 50 units up

therefore

The transformations are

The graph of f(x) is shifted up 50 units

The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

5 0
2 years ago
Read 2 more answers
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