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2 years ago

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Find the outlier in the data: 38, 38, 18, 28, 36, 30, 39, 32. How does the outlier affect the mean? If necessary, round to the n

earest tenth. 43; raises it by 1.5. 18; lowers it by 2. 43; lowers it by 1.5. 18; raises it by 2.

2 answers:

Mashcka [7]2 years ago

8 0

The outlier is 18. This outlier will lower the average mean. The answer is B

Dmitry_Shevchenko [17]2 years ago

6 0

The outlier is 18.
and it lowers the mean by about 2

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One box of crackers costs $1.75. The crackers are advertised as “3 boxes for $5.25.” Which proportion can be used to represent t

Daniel [21]

A. 1/1.75 = 3/5.25

Ignore this part I'm just trying to get at least 20 characters.

5 0

2 years ago

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There were 340,000 cattle placed on feed. Write an equivalent ratio that could be used to find how many of these cattle were bet

lutik1710 [3]

There were 340,000 cattle placed on feed

How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?

Given the fraction of total cattle for 700 - 799 pounds is 2/5

Let x be the number of cattle between 700 - 799 pounds

We make a proportion using the fraction

$\frac{2}{5} = \frac{x}{340,000}$

Cross multiply it and solve for x

340000* 2 = 5x

680000 = 5x

Divide by 5 on both sides

So x= 136,000

There were 136,000 cattle between 700 and 799 pounds

3 0

1 year ago

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A flat circular plate has the shape of the region x squared plus y squared less than or equals 1x2+y2≤1. the plate, including t

vredina [299]

You're looking for the extreme values of $x^2+3y^2+13x$ subject to the constraint $x^2+y^2\le1$ .

The target function has partial derivatives (set equal to 0)

$\dfrac{\partial(x^2+3y^2+13x)}{\partial x}=2x+13=0\implies x=-\dfrac{13}2$

$\dfrac{\partial(x^2+3y^2+13x)}{\partial y}=6y=0\implies y=0$

so there is only one critical point at $\left(-\dfrac{13}2,0\right)$ . But this point does not fall in the region $x^2+y^2\le1$ . There are no extreme values in the region of interest, so we check the boundary.

Parameterize the boundary of $x^2+y^2\le1$ by

$x=\cos u$

$y=\sin u$

with $0\le u$ . Then $t(x,y)$ can be considered a function of $u$ alone:

$t(x,y)=t(\cos u,\sin u)=T(u)$

$T(u)=\cos^2u+3\sin^2u+13\cos u$

$T(u)=3+13\cos u-2\cos^2u$

$T(u)$ has critical points where $T'(u)=0$ :

$T'(u)=-13\sin u+4\sin u\cos u=\sin u(4\cos u-13)=0$

$(1)\quad\sin u=0\implies u=0,u=\pi$

$(2)\quad4\cos u-13=0\implies\cos u=\dfrac{13}4$

but $|\cos u|\le1$ for all $u$ , so this case yields nothing important.

At these critical points, we have temperatures of

$T(0)=14$

$T(\pi)=-12$

so the plate is hottest at (1, 0) with a temperature of 14 (degrees?) and coldest at (-1, 0) with a temp of -12.

4 0

1 year ago

Lisa says that the indicated angles cannot have the same measure. Marita disagrees and says she can prove that they can have the

AlexFokin [52]

I agree with Marita, that the angles could have the same measure. This can be proven if you set the two amounts equal and solve for x.

9x - 25 + x = x + 50 + 2x - 12

To begin, we should combine like terms on both sides of the equation to start simplifying the equation.

10x - 25 = 3x + 38

Next, we should subtract 3x from both sides and add 25 to both sides to get the variable x alone on the left side of the equation.

7x = 63

Finally, we should divide both sides by 7, to get rid of the coefficient of x.

x = 9

If you plug in 9 for x in our first equation, you get that both of the angle measurements equal 65 degrees. This means that Marita is correct, because if x = 9, then the angles would have the same measure.

8 0

1 year ago

the garza family drives to a state park. the remaining distance, in miles, to reach the state park is 285−60x , where x represen

alukav5142 [94]

285 - 60x ; where x represents the number of driving hours.

285 ⇒ <span>The total distance to the state park.
60x </span>⇒<span> </span><span>The number of miles driven after x hours.
60 </span>⇒<span> </span><span>The number of miles driven after 1 hour.

y = 285 - 6x
y </span>⇒<span> </span><span>The number of miles left to drive each day.</span>

5 0

2 years ago

Read 2 more answers