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elena-14-01-66 [18.8K]
1 year ago
8

In ΔKLM, k = 890 inches, ∠M=143° and ∠K=34°. Find the length of m, to the nearest 10th of an inch.

Mathematics
1 answer:
Vesna [10]1 year ago
4 0

Answer: 957.8

Step-by-step explanation:

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The mass of an object is equal to the product of the object's density and volume.
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The answer is A you divide 11.3 by 16
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Beth wants to make exactly 60 blueberry muffins. Each batch makes 6 muffins, She has already made 2.5 batches. How many more bat
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Answer: 4.5

You need that many more batches

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A bar graph titled Album Type Sold per Year has year on the x-axis and number of albums sold on the y-axis. For C D s, in 2008 t
stira [4]

Answer:

True, True, False, True, False, True

Step-by-step explanation:

<u>CDs have a higher mean than digital</u>

<u />

Let's check.  CD mean is (1000 + 800 + 800 + 600 + 400 + 200)/6 = 633.33

Digital mean: (100 + 300 + 300 + 500 + 700 + 900)/6 = 466.67

CD's mean is higher.  Since you are dividing byt he same number you also could have just added the amount and found which was a larger number.  But yes, this is true.

<u>The range of digital is 800</u>

<u />

The range is the highest number inus the lowest number.  For digital the highest is 900 and lowest is 100 so the ange is 900-100 = 800.  So this is true.

<u>The median of CDs is 400. </u>

<u />

The median is the middle value for odd numbers of values, or the average of the two middle values.  6 total values means you have to take the third and fourth and average them.  in CDs the middle values are 800 and 600, the average is 700, so that is what the median is.  this is false.

<u>Both have the same interquartile range. </u>

<u />

Interquartile range is to find the middle number or numbers like in median, then take the two parts it is split into and find the "median" of those.  Then subtract the larger one fromt he smaller one.

IQR of CD the first half is 200, 400, 600 so the middle here is 400, second half has a middle number of 800 so IQR here is 800-400=400

IQR of digital is 700-300 = 400 so yes both are the same.

<u>Both have the same median</u>

<u />

We know the medan of CDs is 700 then findign the median of digital is (300+500)/2 = 400.  So no, the medians are not the same.

<u>Digital’s mean is around 467. </u>

<u />

We founf the mean for digital to be 466.67 which rounds up to 467, So I would say it is true.

8 0
2 years ago
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If h:k = 2:5, x:y=3:4 and 2h+x:k+2y = 1:2, find the ratio h-x: k-y.​
fenix001 [56]

Given:

h:k=2:5,x:y=3:4,2h+x:k+2y=1:2

To find:

h-x:k-y

Solution:

We have, h:k=2:5 and x:y=3:4.

Let the values of h and k are 2a and 5a respectively.

Let the values of x and y are 3b and 4b respectively.

We have,

2h+x:k+2y=1:2

It can be written as

\dfrac{2h+x}{k+2y}=\dfrac{1}{2}

\dfrac{2(2a)+(3b)}{5a+2(4b)}=\dfrac{1}{2}

\dfrac{4a+3b}{5a+8b}=\dfrac{1}{2}

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On further simplification, we get

8a+6b=5a+8b

8a-5a=8b-6b

3a=2b

a=\dfrac{2b}{3}

Now,

h-x:k-y=\dfrac{h-x}{k-y}

h-x:k-y=\dfrac{2-3b}{5a-4b}

h-x:k-y=\dfrac{2\times \dfrac{2b}{3}-3b}{5\times \dfrac{2b}{3}-4b}

h-x:k-y=\dfrac{\dfrac{4b}{3}-3b}{\dfrac{10b}{3}-4b}

On further simplification, we get

h-x:k-y=\dfrac{\dfrac{4b-9b}{3}}{\dfrac{10b-12b}{3}}

h-x:k-y=\dfrac{-5b}{-2b}

h-x:k-y=\dfrac{5}{2}

h-x:k-y=5:2

Therefore, the ratio h-x:k-y is 5:2.

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Answer:

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3) Add all of the values:

$29

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2 years ago
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