The table of this question is in the attachments.
Answer and Step-by-step explanation: <u>Standard</u> <u>deviation</u> is a measure of how spread the data is from the mean. It is calculated as:
s = √∑(x - μ)² / n - 1
where μ is the mean of the set.
<u>Range</u> is the difference between the highest and lowest value of a data set.
(a) <u>Range of Traditional course</u>:
range = 80.4 - 56
range = 24.4
<u>Range of "flipped" course</u>:
range = 92.6 - 63.5
range = 29.1
Comparing ranges, the "flipped" course has more dispersion than the traditional.
(b) <u>Standard Deviation of Traditional course</u>:
mean = 71.6
s = 
s = 8.95
<u>Standard Deviation of "flipped" course</u>:
mean = 77.6
s = 
s = 8.3
Comparing standard deviation, traditional course has more dispersion.
(c) If you change one score, range for traditional will be:
range = 591 - 56
range = 535
Changing one score increase in almost 22 times the range for this category.
Answer:
Equation:

Step-by-step explanation:

They sold 45 Hot Beverages and 180 Cold Beverages
Answer:
Step-by-step explanation:
10+20+40=70
70*0.8=7*10*0.8=56 L (We Deliver)
total area =2*(10+20)*40+2*10*20=2*30*40+400=2400+400=2800 cm^2
2800*0.02=28*100*0.02=28*2=56 L (Go Parcels)
Time taken by Max to cover the same distance walking at 4.2 km/h is 1.5 hours
<h3><u>Solution:</u></h3>
Given it takes Max 1.8 hours to walk home from work at a rate of 3.5km/h
We have to find time taken by Max to cover the same distance walking at 4.2 km/h
<em><u>The relation between speed and time is given as:</u></em>

<em><u>CASE 1:</u></em>
It takes Max 1.8 hours to walk home from work at a rate of 3.5km/h
Let us first find the distance covered
Time taken = 1.8 hours and speed = 3.5 km/hr

Hence distance covered is 6.3 km
<em><u>Now we have to find the time taken to cover same 6.3 km walking at 4.2 km\hr</u></em>

So time taken by Max to cover the same distance walking at 4.2 km/h is 1.5 hours
Answer:
77.76 times
Step-by-step explanation:
The average distance of Neptune from the sun
= 4.503 × 10
⁹ k
m
.
and Mercury = 5.791 × 10
⁷ k
m
.
Hence neptune is ( 4.503 × 10
⁹) ÷ (5.791
×
10
⁷ ) times farther from the sun than mercury
i.e.(
) × 10⁹⁻⁷ times
=
0.7776 × 10
² times
=
77.76 times.