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ivann1987 [24]
2 years ago
12

Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how

many times farther from the sun is Neptune than mercury?
Mathematics
1 answer:
Igoryamba2 years ago
4 0

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune  from the sun

= 4.503  ×  10 ⁹  k m .

and Mercury  =  5.791  ×  10 ⁷ k m .

Hence neptune is (  4.503  ×  10 ⁹) ÷ (5.791 × 10 ⁷  ) times farther from the sun than mercury

i.e.(  \frac{4.503}{5.791} )  × 10⁹⁻⁷ times

=   0.7776  ×  10 ² times

=   77.76  times.

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You gotta move that b to the side ya digg
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A baseball costs $4.00.If the sales tax is 5%,what is the total prics?
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A police car's siren operates at a frequency of 2,000 Hz. What frequency would a stationary listener observe if the police car i
SpyIntel [72]

we can use formula

f_L=f_s(\frac{v_a-v_p}{v_a+v_p} )

where

fL is listener frequency

fs is siren frequency

va is the speed of sound in air

vs is police car speed

so, we have

f_s=2000Hz

v_a=345m/s

v_p=65mph

now, we can change it into m/s

v_p=65*\frac{1609}{3600}m/s

v_p=29.05139m/s

now, we can plug it

f_L=2000(\frac{345-29.05139}{345+29.05139} )

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3 0
2 years ago
How many distinct pairs of disjoint non-empty subsets of A are there, the union of which is all of A?
Mrac [35]
A = {1, 2, 5, 6, 8}
{1} U {2, 5, 6, 8} 
{2} U {1, 5, 6, 8} 
{5} U {1, 2, 6, 8} 
{6} U {1, 2, 5, 8} 
{8} U {1, 2, 5, 6} 
{1, 2} U {5, 6, 8} 
{1, 5} U {2, 6, 8} 
{1, 6} U {2, 5, 8}
{1, 8} U {2, 5, 6} 
{1, 2, 5} U {6, 8} 
{1, 2, 6} U {5, 8}
{1, 2, 8} U {5, 6}
{1, 5, 6} U {2, 8}
{1, 5, 8} U {2, 6}
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The answer is 15 distinct pairs of disjoint non-empty subsets.
5 0
2 years ago
HELP I WILL NAME YOU BRAINLIEST!! Given: Circumscribed polygon ACEG B, H, F, D -points of tangency AB=5, CD=4, DE=3, FG=2 Find:
wolverine [178]

Answer:

perimeter = 28

Step-by-step explanation:

Tangents drawn to a circle from an external point are congruent, thus

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GH = GF = 2

EF = ED = 3

CB = CD = 4

Sum the 8 parts for perimeter of polygon ACEG

perimeter = 5 + 5 + 2 + 2 + 3 + 3 + 4 + 4 = 28

4 0
2 years ago
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