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ivann1987 [24]
1 year ago
12

Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how

many times farther from the sun is Neptune than mercury?
Mathematics
1 answer:
Igoryamba1 year ago
4 0

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune  from the sun

= 4.503  ×  10 ⁹  k m .

and Mercury  =  5.791  ×  10 ⁷ k m .

Hence neptune is (  4.503  ×  10 ⁹) ÷ (5.791 × 10 ⁷  ) times farther from the sun than mercury

i.e.(  \frac{4.503}{5.791} )  × 10⁹⁻⁷ times

=   0.7776  ×  10 ² times

=   77.76  times.

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A 0.2-kilogram red ball is thrown horizontally at a speed of 4 meters per second from a height of 3 meters. A 0.4-kilogram green
Stolb23 [73]

Answer:

option (C) the same

Step-by-step explanation:

In the given question , it is mentioned that the ball of mass 0.2 kilograms is thrown with the velocity of 4 m/s in the horizontal direction

and, the 0.4 kilogram green ball is thrown in the horizontal direction with the velocity of 8 m/s

Here in both the cases no component of velocity in the vertical direction is provided.

Hence, it will be a case of free fall in the vertical direction.

Now,

from Newton's equation of motion, we have

s=ut+\frac{1}{2}at^2

here,  

s is the distance

a is the acceleration

t is the time

in the above equation, mass has no role and the value of acceleration i.e acceleration due to gravity and distance of fall in the vertical direction is same.

Hence, the time taken for both the balls will be same.

Hence,

The correct answer is option (C) the same

7 0
2 years ago
Reza paid $4,500 as a down payment on a car. She then made equal monthly paments of $250. Reza paid a total of $10,500 for her c
monitta
10500-4500=6000

6000/250=24

So the answer is 24 months, or 2 years.
6 0
1 year ago
Solve 5/3x + 1/3x = 13 1/3 + 8/3x then identify x.
belka [17]

After solving \frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x we get value of x = -20

Step-by-step explanation:

We need to solve the fractions and find value of x.

The given fraction is:

\frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x

Solving:

\frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x\\\frac{5}{3}x+\frac{1}{3}x=\frac{40}{3}+\frac{8}{3}x\\ Subtract\,\,\frac{8}{3}x\,\,on\,\,both\,\,sides:\\ \frac{5}{3}x+\frac{1}{3}x-\frac{8}{3}x=\frac{40}{3}+\frac{8}{3}x-\frac{8}{3}x\\Simplifying:\\ \frac{5x+1x-8x}{3}=\frac{40}{3}\\ \frac{-2x}{3}=\frac{40}{3}\\Multiply\,\,both\,\,sides\,\,by\,\,3\\-2x=40\\x=\frac{40}{-2}\\x=-20

So, After solving \frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x we get value of x = -20

Keywords: Solving fractions

Learn more about Solving fractions at:

  • brainly.com/question/2456302
  • brainly.com/question/1648978
  • brainly.com/question/13168205

#learnwithBrainly

3 0
2 years ago
How is a calculation of net worth different from a day-to-day or month-to-month tallying of expenses?
muminat
Net worth includes everything of value you own or could get money for. While month to month expenses is just wages or available spending money
4 0
1 year ago
Read 2 more answers
Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.
alexgriva [62]
Recall that

|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

There are three cases to consider:

(1) When x+2, we have |x+2|=-(x+2) and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4

(2) When x+2\ge0 and x-2, we get |x+2|=x+2 and |x-2|=-(x-2), so

|x-2|+|x+2|=-(x-2)+(x+2)=4

(3) When x-2\ge0, we have |x+2|=x+2 and |x-2|=x-2, so

|x-2|+|x+2|=(x-2)+(x+2)=2x

So

|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x
4 0
1 year ago
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