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ivann1987 [24]
1 year ago
12

Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how

many times farther from the sun is Neptune than mercury?
Mathematics
1 answer:
Igoryamba1 year ago
4 0

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune  from the sun

= 4.503  ×  10 ⁹  k m .

and Mercury  =  5.791  ×  10 ⁷ k m .

Hence neptune is (  4.503  ×  10 ⁹) ÷ (5.791 × 10 ⁷  ) times farther from the sun than mercury

i.e.(  \frac{4.503}{5.791} )  × 10⁹⁻⁷ times

=   0.7776  ×  10 ² times

=   77.76  times.

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Identify the expression equivalent to 4(x + x + 7) − 2x + 8 − 4 by substituting x = 1 and x = 2.
miv72 [106K]
F(1)=4(1+1+7)-2(1)+8-4
f(1)=36+2
f(1)=38

f(2)=4(2+2+7)-2(2)+8-4
f(2)=44

4 0
1 year ago
One winter day, the outside temperature, y, was never below −1°. The inside of a car was always warmer than the temperature outs
mr Goodwill [35]

Answer:

It's C

Step-by-step explanation:

Your graph should be this one, with both lines solid because, the X line, or red, has to be at least -1 or higher, and the Y line, or the blue, has to be +4 or higher

4 0
1 year ago
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What is the true solution to the logarithmic equation below? log Subscript 4 Baseline left-bracket log Subscript 4 Baseline (2 x
Luda [366]

Step-by-step explanation:

log_4(log_4 2x)=1 \\  \\  \therefore \: log_4 2x =  {4}^{1}  \\  \\ \therefore \: log_4 2x =4 \\  \\ \therefore \: 2x =  {4}^{4}  \\  \\ \therefore \: 2x = 256 \\  \\ \therefore \: x =  \frac{256}{2}  \\  \\ \therefore \: x = 128

6 0
2 years ago
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During a field trip, 60 students are put into equal-sized groups. Describe two ways to interpret 60÷5 60 ÷ 5 in this context. Fi
Afina-wow [57]

The second question:

Consider the division expression 7\frac{1}{2} / 2. Select all multiplication equations that correspond to this division expression.

2 * ? = 7\frac{1}{2}     7\frac{1}{2} * ?= 2     ? * 2  = 7\frac{1}{2}

2* 7\frac{1}{2} = ?    ?  * 7\frac{1}{2} = 2

Answer:

1. See Explanation

2. 2 * ? = 7\frac{1}{2}     and     ? * 2  = 7\frac{1}{2}

Step-by-step explanation:

Solving (a):

Given

Students = 60

Group = Equal\ Sized

Required

Interpret \frac{60}{5} in 2 ways

<u>Interpretation 1:</u> Number of groups if there are 5 students in each

<u>Interpretation 2:</u> Number of students in each group if there are 5 groups

<u>Solving the quotient</u>

Quotient = \frac{60}{5}

Quotient = 12

<u>For Interpretation 1:</u>

The quotient means: 12 groups

<u>For Interpretation 2:</u>

The quotient means: 12 students

Solving (b):

Given

7\frac{1}{2} / 2

Required

Select all equivalent multiplication equations

Let ? be the quotient of t 7\frac{1}{2} / 2

So, we have:

7\frac{1}{2}/2 = ?

Multiply through by 2

2 * 7\frac{1}{2}/2 = ? * 2

7\frac{1}{2} = ? * 2

Rewrite as:

? * 2 = 7\frac{1}{2}  --- This is 1 equivalent expression

Apply commutative law of addition:

2 * ? = 7\frac{1}{2}  --- This is another equivalent expression

8 0
1 year ago
What is another way to write 9x200?
pashok25 [27]
9×2=18. add the tow zeros like this 9×2=18+00=1,800
7 0
1 year ago
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