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maks197457 [2]
1 year ago
12

Mustafa, Heloise, and Gia have written more than a combined total of 2222 22 articles for the school newspaper. Heloise has writ

ten 14\dfrac{1}{4} 4 1 ? as many articles as Mustafa has. Gia has written 32\dfrac{3}{2} 2 3 ? as many articles as Mustafa has. Write an inequality to determine the number of articles, mm m , Mustafa could have written for the school newspaper.
Mathematics
2 answers:
Jet001 [13]1 year ago
7 0

Answer:

M>8 and the equation is m+  41 m+23  m>22

Step-by-step explanation:

Mustafa has written more than 888 articles.

Hint #33 / 3

The inequality is:

m+\dfrac{1}{4}m+\dfrac{3}{2}m>22m+  

4 1m+23 m>22m, plus, start fraction, 1, divided by, 4, end fraction, m, plus, start fraction, 3, divided by, 2, end fraction, m, is greater than, 22

The solution set is m>8m>8m, is greater than, 8.

Papessa [141]1 year ago
3 0

Answer: m>8

Mustafa could have written more than 8 articles for the newspaper.

Step-by-step explanation:

Given: Heloise has written 1/4 as many articles as Mustafa has. Gia has written 3/2 as many articles as Mustafa has.

Let m be the number of articles Mustafa writes.

Then articles written by Heloise=\frac{1}{4}m

And articles written by Gia=\frac{3}{2}m

The total number of articles =m+\frac{1}{4}m+\frac{3}{2}m=\frac{4m+m+6m}{4}=\frac{11m}{4}

Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

\frac{11m}{4}>22\\\Rightarrow\ m>\frac{22\times4}{11}\\\Rightarrow\ m>8

Hence, Mustafa could have written more than 8 articles for the newspaper.

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IRISSAK [1]

Answer:

a) 0.9

b) Mean = 1.58

Standard Deviation = 0.89

Step-by-step explanation:

We are given the following in the question:

A marketing firm is considering making up to three new hires.

Let X be the variable describing the number of hiring in the company.

Thus, x can take values 0,1 ,2 and 3.

P(x\geq 2) = 50\%= 0.5\\P(x = 0) = 10\% = 0.1\\P(x = 3) = 18\% = 0.18

a) P(firm will make at least one hire)

P(x\geq 2) = P(x=2) + P(x=3)\\0.5 = P(x=2) + 0.18\\ P(x=2) = 0.32

Also,

P(x= 0) +P(x= 1) + P(x= 2) + P(x= 3) = 1\\ 0.1 + P(x= 1) + 0.32 + 0.18 = 1\\ P(x= 1) = 1- (0.1+0.32+0.18) = 0.4

\text{P(firm will make at least one hire)}\\= P(x\geq 1)\\=P(x=1) + P(x=2) + P(x=3)\\ = 0.4 + 0.32 + 0.18 = 0.9

b) expected value and the standard deviation of the number of hires.

E(X) = \displaystyle\sum x_iP(x_i)\\=0(0.1) + 1(0.4) + 2(0.32)+3(0.18) = 1.58

E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89

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2 years ago
ACD is a triangle and B is a point on AC. AB = 8cm and BC is 6cm. Angle BCD = 48° and angle BDC = 50°. (a) Find the length of BD
FromTheMoon [43]

Answer:

  • 5.8206 cm
  • 10.528 cm
  • 23.056 cm^2

Step-by-step explanation:

(a) The Law of Sines can be used to find BD.

  BD/sin(48°) = BD/sin(50°)

  BD = (6 cm)(sin(48°)/sin(60°)) ≈ 5.82064 cm

__

(b) We can use the Law of Cosines to find AD.

  AD^2 = AB^2 +BD^2 -2·AB·BD·cos(98°) . . . . . angle ABD = 48°+50°

  AD^2 ≈ 110.841

  AD ≈ √110.841 ≈ 10.5281 . . . cm

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(c) The area of ∆ABD can be found using the formula ...

  A = ab·sin(θ)/2 . . . . . where a=AB, b=BD, θ = 98°

  A = (8 cm)(5.82064 cm)sin(98°)/2 ≈ 23.0560 cm^2

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Angle ABD is the external angle of ∆BCD that is the sum of the remote interior angles BCD and BDC. Hence ∠ABD = 48° +50° = 98°.

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What is the multiplicative rate of change for the exponential function f(x) = f start bracket x end bracket equals two start bra
jeka94

Answer:

The multiplicative rate of change is \dfrac{2}{5}.

Step-by-step explanation:

You are given the function

f(x)=2\cdot \left(\dfrac{5}{2}\right)^{-x}

First, use the following property of exponents

\left(\dfrac{a}{b}\right)^{-x}=\left(\dfrac{b}{a}\right)^{x}

So, your function is

f(x)=2\cdot \left(\dfrac{2}{5}\right)^{x}

If the exponential function is written in the form

f(x)=a\cdot b^x,

then b is the multiplicative rate of change for this exponential function.

In your case, the multiplicative rate of change is \dfrac{2}{5}.

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C

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Therefore, the function that belongs to this graph is

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