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2 years ago

Which expression is modeled by this arrangement of tiles?

Mathematics

2 answers:

skad [1K]2 years ago

7 0

Answer:

The Right answer is C 40/10

Step-by-step explanation:

40/10 because there are 4 blocks in each set, there are 10 sets, and all the blocks are positive.

(Please mark me Brainliest .....)

Gnoma [55]2 years ago

6 0

Answer:

The answer is 16 ÷ 2 = 8.

Step-by-step explanation:

Now, to find the expression modeled by arrangement of tiles.

So, according to the model in the question.

There are 16 tiles in the model.

So, arrangement of 16 tiles divided into 2 groups.

Where each group consist 8 tiles.

So, we can write as:

$16\div 2$

As 16 is the number of tiles and 2 is the number of groups.

Now, we can check the expression by doing the division.

$16\div 2 = 8$

Therefore, each group has 8 tiles.

You might be interested in

Two opposing opinions were shown to a random sample of 1,744 US buyers of a particular political news app. The opinions, shown i

sweet-ann [11.9K]

Answer:

95% confidence interval for the proportion of all US buyers who would have chosen Opinion A is [0.28 , 0.32].

Step-by-step explanation:

We are given that Two opposing opinions were shown to a random sample of 1,744 US buyers of a particular political news app.

The outcomes were as follows: 30% chose Opinion A, 64% chose Opinion B, and 6% chose "Neutral."

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of US buyers who chose Opinion A = 0.30

n = sample of US buyers = 1,744

p = population proportion

Here for constructing 95% confidence interval we have used One-sample z test for proportions.

(a) SO, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.30-1.96 \times {\sqrt{\frac{0.30(1-0.30)}{1,744} } }$ , $0.30+1.96 \times {\sqrt{\frac{0.30(1-0.30)}{1,744} } }$ ]

= [0.28 , 0.32]

Therefore, 95% confidence interval for the proportion of all US buyers who would have chosen Opinion A is [0.28 , 0.32].

(b) The number of buyers that chose Opinion A and the number of buyers that did not choose Opinion A are both greater than 10, that is;

Number of buyers that did chose Opinion A = $n \times p$

= $1,744 \times 0.30$ = 523.2

Number of buyers that did not chose Opinion A = $n \times (1-p)$

= $1,744 \times 0.70$ = 1220.8

Now, this inference condition should have been met because if these were not met then we were not able to use the normal distribution statistics above because binomial distribution can be converted to normal distribution only when $np$ and $n(1-p)$ both are greater than 10.

8 0

2 years ago

The price of salmon at a Fish market is $5.40 per pound this is 150 percent of its price at the supermarket how much would it co

REY [17]

Fish market = $5.4
supermarket = 150% of $5.4
150% - - > 1.5
so the cost at the supermarket is 1.5*5.4=8.1.

8 0

2 years ago

Read 2 more answers

Evaluate 1/3 m - 1 - 1/2 n when m = 21 and n = 12

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

1/3(21)-1-1/2(12)

7-1-6=6-6=0

3 0

2 years ago

Pencils come in boxes of 10. How many boxes should Erika buy if she needs 127 pencils?

matrenka [14]

She'll need 13 boxes! 10 divided by 127 is 12 and there's a remainder of 7. so seven crayons will fill the 13th box :)

5 0

2 years ago

What is the difference of the polynomials? (8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4)

Dafna1 [17]

(8r^6s^3 – 9r^5s^4 + 3r^4s^5) – (2r^4s^5 – 5r^3s^6 – 4r^5s^4)
= 8r^6s^3 – 9r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6 + 4r^5s^4
= 8r^6s^3 – 9r^5s^4 + 4r^5s^4 + 3r^4s^5 – 2r^4s^5 + 5r^3s^6
= 8r^6s^3 – 5r^5s^4 + r^4s^5 + 5r^3s^6

Hope it helps

4 0

2 years ago

Read 2 more answers