Answer:
The probability that no flaws occur in a certain portion of wire of length 5 millimeters = 1.1156 occur / millimeters
Step-by-step explanation:
<u>Step 1</u>:-
Given data A copper wire, it is known that, on the average, 1.5 flaws occur per millimeter.
by Poisson random variable given that λ = 1.5 flaws/millimeter
Poisson distribution 
<u>Step 2:</u>-
The probability that no flaws occur in a certain portion of wire
On simplification we get
P(x=0) = 0.223 flaws occur / millimeters
<u>Conclusion</u>:-
The probability that no flaws occur in a certain portion of wire of length 5 millimeters = 5 X P(X=0) = 5X 0.223 = 1.1156 occur / millimeters
34/100
= 0.34
3 tenths, 4 hundreths
Answer:
48 cm
Step-by-step explanation:
Given:
Distance of rod from the wall = 45 cm
Distance of rod from the light = 15 cm
Length of rod = 12 cm
We can see that <DAM and <BAF are equal
Also, <DMA and <BFM are equal because they are corresponding angles
To find the length of the shadow, let's take the equation
Where.:
DM = ½ of length of the rod = ½*12 = 6
A.F = 15 + 45 = 60 cm
AM = 15 cm
Therefore,
Cross multiplying, we have:
15 * B.F = 60 * 6
15 * B.F = 360
BF = 24 cm
The shadow on the wall =
2 * BF
= 2 * 24
= 48 cm
The shadow on the wall is 48 cm
Answer:
$61.69 You take the 15.5 and take off the .5 to begin with so you start with 15 multiply it by 3.98 to get 59.7 then you take 3.98 divide it by 2 because the .5 is the same thing as 1/2 then you get 1.99 then you add it to your 59.7 to get 61.69 and thats your answer. Hope this helps :)
Answer:
The equivalent of 5.651 mi is 9945.76 yards
Step-by-step explanation:
Given:
Length of lake = 5.651 mi
Required:
Length of bridge in yards
From table of facts;
1 mile = 1760 yards
This implies that
5.651 miles will be:5.651 * 1760 yards
5.651 * 1760 yards = 9945.76 yards
5.651 * 1760 yards = 9945.8 yards (Aproximated)
Hence, the equivalent of 5.651 mi is 9945.76 yards
